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3 years ago

Work out the percentage change to 2 decimal places when a price of £57.99 is decreased to £49.99.

Mathematics

1 answer:

IRISSAK [1]3 years ago

5 0

Answer:

Percentage change in price = 13.80%

Step-by-step explanation:

Given that:

Original price = £57.99

Decreased price = £49.99

Difference = Original price - Decreased price

Difference = 57.99 - 49.99

Difference = £8.00

Percent change = $\frac{Difference}{Original\ price}100$

Percent change = $\frac{8.00}{57.99}*100$

Percent change in price = 13.80%

Hence,

Percentage change = 13.80%

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Solve 7x − 2y = −3<br> 14x + y = 14

Sauron [17]

7x - 2y = -3

14x + y = 14
14x -14x + y = 14-14x
Y = 14 - 14x

7x -2y = -3
7x - 2(14 - 14x) = -3
7x -28 + 28x = -3
7x + 28x - 28 = -3
35x - 28 = -3
35x - 28 + 28 = -3 + 28
35x = 25
35x/35 = 25/35
X = 25/35 = 5/7.

Y = 14 - 14x
Y = 14 - 14(5/7)
Y = 14 - 10
Y = 4.

The solution P(5/7,4).

8 0

3 years ago

Read 2 more answers

A customer brings a check of 2,941. he wants 100 in cash, put 20% of the remaining into her savings account then the rest into a

Goryan [66]

Answer:

Amount theta she is putting in Checking account is 2272.80

Step-by-step explanation:

Given:

Amount on check = 2941

Amount that he want in cash = 100

Amount she put in saving account = 20% of remaining after getting cash

Remaining Amount she put in checking account.

To find: Amount in her Checking Account.

Amount left after taking cash = 2941 - 100 = 2841

Amount that she put in saving account = 20% of 2841 = $\frac{20}{100}\times2841$ = 568.20

Amount in her checking account = 2941 - 100 - 568.20 = 2272.8

Therefore, Amount theta she is putting in Checking account is 2272.80

8 0

3 years ago

PLS HELP!!<br><br> What values of u and v make triangle XYZ = Triangle GFH

Katarina [22]

Answers:

u = 18

v = 20

========================================================

Work Shown:

The leg YZ is congruent to the left FH

This means YZ = FH and that leads to u+v-18 = 10u-8v

The hypotenuse ZX is congruent to the hypotenuse HG

This means ZX = HG and we get the equation 14v-14u+32 = v+u+22

----------------------

The system of equations we have so far is

u+v-18 = 10u-8v

14v-14u+32 = v+u+22

Let's get the equations into standard form

Start with the first equation

u+v-18 = 10u-8v

u+v = 10u-8v+18

u+v-10u+8v = 18

-9u+9v = 18

-9(u-v) = 18

u-v = 18/(-9)

u-v = -2

Note how we can solve for the variable u to get

u = v-2

which we'll use later

----------------------

Let's get the other equation into standard form as well

14v-14u+32 = v+u+22

14v-14u-v-u = 22-32

-15u+13v = -10

Now plug in u = v-2 and solve for v

-15u+13v = -10

-15(v-2) + 13v = -10

-15v+30+13v = -10

-2v+30 = -10

-2v = -10-30

-2v = -40

v = -40/(-2)

v = 20

Which means,

u = v-2

u = 20-2

u = 18

3 0

2 years ago

Select the statement which is true about the functions over the interval [1, 2].

givi [52]

Answer:

i want to say it is b but i could be wrong

Step-by-step explanation:

6 0

3 years ago

F(x)=(x+1)(x+3)(x-4) in standard form

Yuri [45]

Answer:

f(x) = $x^{3}-13x-12$

Step-by-step explanation:

3 0

2 years ago