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nadezda [96]
1 year ago
6

Function rule how to solve ​

Mathematics
1 answer:
JulsSmile [24]1 year ago
7 0

Step-by-step explanation:

please mark me as brainlest

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10. George earns $455 per week. He receives a 20% raise. What is George's new weekly salary?
djverab [1.8K]

Answer:

$546

Step-by-step explanation:

455*.20=91  

91+455+546

8 0
3 years ago
Read 2 more answers
Which expression is equivalent to -9a-10-6a+7−9a−10−6a+7
Gwar [14]

Answer:

−30a−6

Step-by-step explanation:

Let's simplify step-by-step.

−9a−10−6a+7−9a−10−6a+7

=−9a+−10+−6a+7+−9a+−10+−6a+7

Combine Like Terms:

=−9a+−10+−6a+7+−9a+−10+−6a+7

=(−9a+−6a+−9a+−6a)+(−10+7+−10+7)

=−30a+−6

BRAINLIEST. if you don't mind.

6 0
2 years ago
7 earn 5 coins
Sergio039 [100]
The answer is 9 cubic units
5 0
2 years ago
Exponential function f is represented by the table. x -2 -1 0 1 2 f(x) -46 -22 -10 -4 -1 Function g is represented by the equati
Scrat [10]

The statement that describes better about function is "Both functions are increasing, but function g increases at a faster average rate." since option (c) is correct.

Given the table

x         f(x)

-2        -46

-1         -22

0         -10

1           -4

2          -1

We have to choose which statement describes better about function

Let us assume f(x)=ab^x+c

at x=0, f(0)=-10

So, -10 =a+c

Similarly, by satisfying the above table in the f(x)

f(x)=\frac{33}{5} (\frac{1}{11})^x-\frac{17}{5}

f'(x) > 0

So we can say that f(x) is an increasing function.

g(x) = - 18  (\frac{1}{3}  )^ x + 2

g^ \prime (x) = - 18 (\frac{1}{3}  )^ x  ln(1/3)

ln(1/3) < 0

So, g^ \prime (x) > 0

So, g(x) is an increasing function.

For any x∈f(x) and  x∈g(x) g'(x) > f'(x)

So, g increases at a faster average rate

Thus, Both functions are increasing, but function g increases at a faster average rate.

Learn more about increasing functions here: brainly.com/question/12940982

#SPJ10

7 0
1 year ago
Anna baked <br> 3 batches of cookies with <br> c cookies in each batch. She then ate <br> 8 cookies!
Romashka [77]

If your looking for the equation...

3c-8

8 0
3 years ago
Read 2 more answers
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