How much work is done on a small car if a 3150 N force is exerted to move it 75.5 m to the side of the road?
1 answer:
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Let's use the mirror equation to solve the problem:
where f is the focal length of the mirror,
the distance of the object from the mirror, and 
the distance of the image from the mirror.
For a concave mirror, for the sign convention f is considered to be positive. So we can solve the equation for by using the numbers given in the text of the problem:
Where the negative sign means that the image is virtual, so it is located behind the mirror, at 8.6 cm from the center of the mirror.
where f is the focal length of the mirror,
For a concave mirror, for the sign convention f is considered to be positive. So we can solve the equation for
Where the negative sign means that the image is virtual, so it is located behind the mirror, at 8.6 cm from the center of the mirror.
Answer:
(a) 1000 N/C
Explanation:
Kinetic energy of electron, K = 1.6 x 10^-17 J
distance, d = 10 cm = 0.1 m
Let the potential difference is V and the electric field is E.
(a) The relation between the kinetic energy and the potential difference is
K = e V
V = K / e
Where, e be the electronic charge = 1.6 x 10^-19 C
V =
V = 100 V
The relation between the electric field and the potential difference is given by
V = E x d
100 = E x 0.1
E = 1000 N/C
(b) The force acting on the electron, F = q E
where q be the charge on electron
So, F = -e x E
It means the direction of electric field and the force are both opposite to each other.
The direction of electric field and the force on electron is shown in the diagram.
Answer:
<em>14.07 units of joules is removed for each joules of electricity used</em>
Explanation:
The heated room temperature = 61 °F
The outside temperature = 98 °F
For conversion from fahrenheit to kelvin we use the equation
(32°F − 32) × 5/9 + 273.15
= 289.26
= 309.82
For air conditioning,
COP =
COP = = 14.07
This means that <em>14.07 units of joules is removed for each joules of electricity used</em>