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3 years ago

11

A Carnot air conditioner takes energy from the thermal energy of a room at 61°F and transfers it as heat to the outdoors, which

is at 98°F. For each joule of electric energy required to operate the air conditioner, how many joules are removed from the room?

1 answer:

anyanavicka [17]3 years ago

8 0

Answer:

<em>14.07 units of joules is removed for each joules of electricity used</em>

Explanation:

The heated room temperature $T_{c}$ = 61 °F

The outside temperature $T_{h}$ = 98 °F

For conversion from fahrenheit to kelvin we use the equation

(32°F − 32) × 5/9 + 273.15

$T_{c}$ = 289.26

$T_{h}$ = 309.82

For air conditioning,

COP = $\frac{T_{c} }{T_{h} -T_{c} }$

COP = $\frac{289.26 }{309.82 -289.26 }$ = 14.07

This means that <em>14.07 units of joules is removed for each joules of electricity used</em>

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From the question we are told that

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