Answer: No
Currently we don't have enough information to prove this quadrilateral is a parallelogram. One piece of information that would be useful would be if the other diagonal is bisected. If that's the case, then we have a parallelogram (we would first prove the triangles congruent and then use the corresponding congruent angles to set up the parallel lines). Unfortunately, we only know about one diagonal being bisected, but not both, so we don't have enough info.
Answer:
solution
given=3a+3a^2+3a^3+....+...+...3an
first term(t1)=3a
second term(t2)=3a^2
third term(t3)=3a^3
for arithmetic mean ,d1=d2
d1=t2_t1=3a^2_3a=3a(a_1)
d2=3a^3_3a^2=3a^2(a_1)
here d1 is not equal to d2.
so it's not an arithmetic series.
Again,for geometric mean,r1=r2
r1=d2/d1=3a^2/3a=a
r2=d3/d2=3a^3/3a^2=a
here ,r1 is equal to r2.
so ,it's an geometric series.
To solve this question, it is needed to know that the sum of the digits of numbers which are multiples of 9 greater than 1, add to 9, that is:
Multiples of 9:
9*1 = 9
9*2 = 18 -> 1 + 8 = 9
9*3 = 27 -> 2 + 7 = 9
9*4 = 36 -> 3 + 6 = 9
9*5 = 45 -> 4 + 5 = 9
Find a number:
Thus, there are 4 possible options for the desired 2-digit number less than 50:
18, 27, 36, 45.
For more, you can check brainly.com/question/24294485
6.21 --subtract 1.05 from 7.26
Step-by-step explanation:
only 9 points uneceptable
