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3 years ago

15

In preparing to shoot an arrow, an archer pulls a bow string back 0.424 m by exerting a force that increases uniformly from 0 to

223 N. What is the equivalent spring constant of the bow?

1 answer:

Wittaler [7]3 years ago

8 0

Answer:

525.94N/m

Explanation:

According to Hooke's law, the extension or compression of an elastic material is proportional to an applied force provided that the elastic limit of the material is not exceeded.

$F=ke..................(1)$

where F is the applied force or load, k is the elastic constant or stiffness of the material and e is the extension.

In this problem, the bow string is assumed to behave like an elastic material that is stretched not beyond the elastic limit.

Given;

F = 223N;

e = 0.424m

k = ?

We make substitutions into equation (1) and then solve for k.

$223=k*0.424\\k=\frac{223N}{0.424m}\\k = 525.94N/m$

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Katyanochek1 [597]

Answer:

The force is $F = 1041.7N$

Explanation:

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$= 0.207kgm^2$

The torque on the wheel due to net force is mathematically represented as

$\tau = FR_B - F_rR_A$

Substituting 135 N for $F_r$ (Force acting on sprocket), $\frac{8.7cm}{2} * \frac{1m}{100cm} = 0.0435m$ for $R_B$ (radius of the chain) and F is the force acting on the sprocket due to the chain which is unknown for now

$\tau = F (0.0435) - 135 (0.33)$

This same torque due to the net force is the also the torque that is required to rotate the wheel to have an angular acceleration of $\alpha = 3.70 rad/s^2$ and this torque can also be represented mathematically as

$\tau = \alpha I$

Now equating the two equation for torque

$F (0.0435) - 135 (0.33) = \alpha I$

Making F the subject

$F = \frac{\alpha I + (135*0.33) }{0.0435}$

Substituting values

$F = \frac{(3.70 * 0.207) + (135*0.33)}{0.0435}$

$= 1041.7N$

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A long point-object, mass = 1.0 kg, moves in a circular path at a radial distance = 0.5 m from the axis of rotation. What is the

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Explanation:

Given

mass of Point object $m=1 kg$

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Also Moment of Inertia tells about the distribution of mass over the given region with respect to center of mass.

Therefore $I=mr^2$

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3 years ago

A gardener mows a lawn with an old-fashioned push mower. The handle of the mower makes an angle of 320 with the surface of the l

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Answer:

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Explanation:

∅ = 32º

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N = ?

We can apply:

∑ F = 0 (↑)

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⇒ F*Sin ∅ + m*g = N

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⇒ N = 337.96 N (↑)

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3 years ago