In preparing to shoot an arrow, an archer pulls a bow string back 0.424 m by exerting a force that increases uniformly from 0 to
1 answer:
Answer:
525.94N/m
Explanation:
According to Hooke's law, the extension or compression of an elastic material is proportional to an applied force provided that the elastic limit of the material is not exceeded.
where F is the applied force or load, k is the elastic constant or stiffness of the material and e is the extension.
In this problem, the bow string is assumed to behave like an elastic material that is stretched not beyond the elastic limit.
Given;
F = 223N;
e = 0.424m
k = ?
We make substitutions into equation (1) and then solve for k.
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y(4) = ½(-9.8)4² = -78.4 m
x(6) = 30(6) = 180 m
y(6) = ½(-9.8)6² = -176.4 m
x(8) = 30(8) = 240 m
y(8) = ½(-9.8)8² = -313.6 m
x(10) = 30(10) = 300 m
y(10) = ½(-9.8)10² = -490 m
