Question

Please help me do this question I will really appreciate it

Answer 1

Answer:

all $\sqrt{89}$

Step-by-step explanation:

Calculate the lengths using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = J(- 2, - 2) and (x₂, y₂ ) = J'(3, 6)

JJ' = $\sqrt{(3+2)^2+(6+2)^2}$ = $\sqrt{5^2+8^2}$ = $\sqrt{25+64}$ = $\sqrt{89}$

Repeat with

(x₁, y₁ ) = K(- 8, - 4) and (x₂, y₂ ) = K'(- 3, 4)

KK' = $\sqrt{(-3+8)^2+(4+4)^2}$ = $\sqrt{5^2+8^2}$ = $\sqrt{25+64}$ = $\sqrt{89}$

Repeat with

(x₁, y₁ ) = L(- 6, - 6) and (x₂, y₂ ) = L'(- 1, 2)

LL' = $\sqrt{(-1+6)^2+(2+6)^2}$ = $\sqrt{5^2+8^2}$ = $\sqrt{25+64}$ = $\sqrt{89}$

Answer 2

Answer:

Repeat with

(x₁, y₁ ) = L(- 6, - 6) and (x₂, y₂ ) = L'(- 1, 2)

LL' = \sqrt{(-1+6)^2+(2+6)^2}

(−1+6)

2

+(2+6)

2

= \sqrt{5^2+8^2}

5

2

+8

2

= \sqrt{25+64}

25+64

= \sqrt{89}

89

Step-by-step explanation:

Repeat with

(x₁, y₁ ) = L(- 6, - 6) and (x₂, y₂ ) = L'(- 1, 2)

LL' = \sqrt{(-1+6)^2+(2+6)^2}

(−1+6)

2

+(2+6)

2

= \sqrt{5^2+8^2}

5

2

+8

2

= \sqrt{25+64}

25+64

= \sqrt{89}

89