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BaLLatris [955]
3 years ago
9

Which component of a galaxy is found in the space between the stars and gives the appearance of bright, colorful clouds?(2 point

s)
1. Clouds
2. Gas
3. Object
4. Star
Physics
2 answers:
DerKrebs [107]3 years ago
4 0

Answer:

stars

Explanation:

fgiga [73]3 years ago
3 0
Star


. ....................
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If a point has 40 J of energy and the electric potential is 8 V, what must be the charge?
Alekssandra [29.7K]

If a point has 40 J of energy and the electric potential is 8 V, the charge must be: A. 5 C

<u>Given the following the details;</u>

  • Energy = 40 Joules
  • Electric potential = 8 Volts

To find the quantity of charge;

Mathematically, the quantity of charge with respect to electric potential is given by the formula;

Quantity \; of \; charge = \frac{Energy}{Electric \; potential}

Substituting the values into the formula, we have;

Quantity \; of \; charge = \frac{40}{8}

<em>Quantity of charge = 5 Coulombs</em>

Therefore, the quantity of charge must be <em>5 Coulombs.</em>

Find more information: brainly.com/question/21808222

8 0
3 years ago
Read 2 more answers
Two blocks, stacked one on top of the other, slide on a frictionless horizontal surface. The surface between the two blocks is r
devlian [24]

Answer:

F_{net} = 31.88 N

Explanation:

When top block is just or about to slide on the lower block then we can say that the frictional force on it will be maximum static friction

So we will have

F_{net} = ma

F_s = ma

\mu_s mg = ma

a = \mu_s g

a = (0.50)(9.81)

a = 4.905 m/s^2

now for the Net force on two blocks to move together

F_{net} = (m_1 + m_2) a

F_{net} = (2.3 + 4.2)(4.905)

F_{net} = 31.88 N

4 0
3 years ago
What has an ionised atom lost or gained?<br> Protons<br> Gamma Rays<br> Electrons<br> Neutrons
vagabundo [1.1K]

Answer:

Electrons

Explanation:

Ionised atoms loose and gain electrons.

hope it helps!

6 0
3 years ago
What unit is commonly used when measuring the energy rating of an electrical appliance
lapo4ka [179]

usually it is watts

8 0
3 years ago
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The car has a constant deceleration of 4.20 m/s^2. If its initial velocity was 24.0 m/s, how long does it take to come to a stop
nalin [4]

Answer:

The time is 5.71 sec.

Explanation:

Given that,

Acceleration a= -4.20 m/s^2

Initial velocity = 24.0 m/s

We need to calculate the time

Using equation of motion

v = u+at[/tex]

Where, v = final velocity

u = inital velocity

t = time

a = acceleration

Put the value into the formula

0 =24.0 +(-4.20)\times t

t = \dfrac{-24.0}{-4.20}

t=5.71\ sec

Hence, The time is 5.71 sec.

5 0
4 years ago
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