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BaLLatris [955]

3 years ago

9

Which component of a galaxy is found in the space between the stars and gives the appearance of bright, colorful clouds?(2 point

s)
1. Clouds
2. Gas
3. Object
4. Star

2 answers:

DerKrebs [107]3 years ago

4 0

Answer:

stars

Explanation:

fgiga [73]3 years ago

3 0

Star

. ....................

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Captain American throws his shield straight down off a roof with a speed of 50 m/s . What is the acceleration of the shield half

Nutka1998 [239]

<em>IF</em> this is happening on <u>Earth</u>, then the acceleration of gravity wherever the captain and the roof are is about 9.8 m/s² downward.

<em>IF</em> his shield is not affected by air resistance, and it's free to behave under the influence of gravity alone, then its acceleration is <em>9.8 m/s² downward</em>, from the moment it leaves his hand until the moment it hits a building, a tree, a car, a bus, an evildoer, or the ground.

Whatever speed it has when it leaves his hand, in whatever direction, makes no difference.

6 0

3 years ago

An oil layer that is 5.0 cm thick is spread smoothly and evenly over the surface of water on a windless day. A light ray from th

marshall27 [118]

Answer:

The angle of refraction in water 32.12°.

Explanation:

Given that,

Thickness = 5.0 cm

Index of refraction for oil = 1.15

Index of refraction for water = 1.33

Angle = 45°

We need to calculate the angle of refraction

When the ray of light enters from air to oil

Using formula of refraction

$n_{a}\sin\theta_{a}=n_{o}\sin\theta_{o}$

Where, $n_{a}$ = refractive index of air

$n_{0}$ = refractive index of oil

Put the value into the formula

$1\times\sin45=1.15\sin\theta_{o}$

$\sin\theta_{o}=\dfrac{1}{\sqrt{2}\times1.15}$

$\sin\theta_{o}=0.6148$

$\theta_{o}=sin^{-1}0.6149$

$\theta_{o}=37.94^{\circ}$

When the ray of light enters from oil to water

Using formula of refraction

$n_{0}\sin\theta_{0}=n_{w}\sin\theta_{w}$

Where, $n_{w}$ = refractive index of water

$1.15\times\sin37.94^{\circ}=1.33\sin\theta_{w}$

$\sin\theta_{w}=\dfrac{1.15\sin37.94^{\circ}}{1.33}$

$\theta_{w}=\sin^{-1}0.53163$

$\theta_{w}=32.12^{\circ}$

Hence, The angle of refraction in water 32.12°.

7 0

3 years ago

As air becomes warmer, it

shutvik [7]

As air becomes warmer it condensates

3 0

3 years ago

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An electronic line judge camera captures the impact of a 57.0-g tennis ball traveling at 32.2 m/s with the side line of a tennis

mote1985 [20]

Answer:

average acceleration is 1.365 × $10^{4}$ m/s²

Explanation:

given data

initila speed u = -32.2 m/s

final speed v = 21.6 m/s

time taken t = 0.00394 s

solution

we get here average acceleration that will be express as

v = u + at ..........................1

put here value and we get

21.6 = -32.2 + a × 0.00394

solve it we get

a = 1.365 × $10^{4}$ m/s²

so average acceleration is 1.365 × $10^{4}$ m/s²

3 0

3 years ago

What is happening in the picture?

Veseljchak [2.6K]

The gravity is pushing rhe boat down

3 0

3 years ago

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