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kkurt [141]
3 years ago
15

What unit is used to measure the amount of energy that people get from food?

Physics
1 answer:
3241004551 [841]3 years ago
4 0
Calories... I think Hopefully It's the right answer.
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A 15-g bullet pierces a sand bag that is 48cm thick. The initial speed of the bullet is 39 m/s and it emerged from the sandbag a
Alik [6]
We can use the conservation of energy to solve this problem. 

We know the bullet goes in at 39m/s and leaves with 27m/s and some energy lost. We can model this using the kinetic equation energy.

\frac{1}{2}(0.015)(39)^2 = \frac{1}{2}(0.015)(27)^2 +U_{L}

The "U" is the energy lost when the bullet went through the bag. Solving for U, we get:

U= \frac{1}{2}(0.015)(39)^2- \frac{1}{2}(0.015)(27)^2= 5.94J

Next we know the bag is 48cm thick and that F*d=W, rearranging this equation we get:

F= \frac{W}{d} =  \frac{(5.94J)}{0.48m} = 12.375N

F = 12.375N

7 0
3 years ago
A 0.0502-kg pair of fuzzy dice is attached to the rearview mirror of a car by a short string. The car accelerates at constant ra
Sauron [17]

Answer:

a = 0.55 m/s/s

Explanation:

As the car accelerates in forward direction the string will make some angle with the vertical direction

So here horizontal component of the tension force will accelerates the dice in forward direction along with the car

Vertical component of the tension force will balance the weight of the dice

so we will have

Tcos\theta = mg

Tsin\theta = ma

here we know that

\theta = angle made with the vertical by string

now divide the two equations

\frac{sin\theta}{cos\theta} = \frac{ma}{mg}

so we have

a = g tan\theta

a = 9.81 tan3.20

a = 0.55 m/s^2

7 0
3 years ago
A 60 kg adult and a 30kg child are passengers on a rotor ride at an amusement park as shown in the diagram above. When the rotat
Ulleksa [173]

Answer:

 fr ’= ½ F

Explanation:

For this exercise we use the translational equilibrium equation, on the axis parallel to the wall

              fr - W = 0

              fr = W

for the adult man they indicate that the friction force is equal to F

              F = M g

we write the equilibrium equation for the child

             fr ’= w’

             fr ’= m g

in the statement they tell us that the mass of the adult is 2 times the mass of the child

             M = 2m

we substitute

            fr ’= M / 2 g

            fr ’= ½ Mg

we substitute

            fr ’= ½ F

therefore the force of friction in the child is half of the friction in the adult

8 0
2 years ago
What is a factor that limits a technological design?
Ivanshal [37]
The answer is a constraint
5 0
3 years ago
Read 2 more answers
I.Name two commonly used thermometric liquids.
PtichkaEL [24]

Answer:

mercury and alcohol

ii) used to test temperatures

6 0
3 years ago
Read 2 more answers
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