We can use the conservation of energy to solve this problem.
We know the bullet goes in at 39m/s and leaves with 27m/s and some energy lost. We can model this using the kinetic equation energy.

The "U" is the energy lost when the bullet went through the bag. Solving for U, we get:

Next we know the bag is 48cm thick and that F*d=W, rearranging this equation we get:
F = 12.375N
Answer:
a = 0.55 m/s/s
Explanation:
As the car accelerates in forward direction the string will make some angle with the vertical direction
So here horizontal component of the tension force will accelerates the dice in forward direction along with the car
Vertical component of the tension force will balance the weight of the dice
so we will have


here we know that
= angle made with the vertical by string
now divide the two equations

so we have



Answer:
fr ’= ½ F
Explanation:
For this exercise we use the translational equilibrium equation, on the axis parallel to the wall
fr - W = 0
fr = W
for the adult man they indicate that the friction force is equal to F
F = M g
we write the equilibrium equation for the child
fr ’= w’
fr ’= m g
in the statement they tell us that the mass of the adult is 2 times the mass of the child
M = 2m
we substitute
fr ’= M / 2 g
fr ’= ½ Mg
we substitute
fr ’= ½ F
therefore the force of friction in the child is half of the friction in the adult
The answer is a constraint
Answer:
mercury and alcohol
ii) used to test temperatures