Calculate the vapor pressure of a solution containing 25.2 gg of glycerin (C3H8O3)(C3H8O3) in 124 mLmL of water at 30.0 ∘C∘C. Th
1 answer:
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Answer: 60.7 g of will be formed.
Explanation:
To calculate the moles :
The balanced chemical reaction is
is the limiting reagent as it limits the formation of product and
is the excess reagent.
According to stoichiometry :
6 moles of produce = 4 moles of
Thus 2.68 moles of will produce=
of
Mass of
Thus 60.7 g of will be formed by reactiong 60 L of hydrogen gas with an excess of
Answer: -
12.41 g
Explanation: -
Mass of CO₂ = 42 g
Molar mass of CO₂ = 12 x 1 + 16 x 2 = 44 g / mol
Number of moles of CO₂ =
= 0.9545 mol
The balanced chemical equation for this process is
2C₆H₆ + 15O₂ → 12CO₂ + 6H₂O
From the balanced chemical equation we see
12 mol of CO₂ is produced from 2 mol of C₆H₆
0.9545 mol of CO₂ is produced from
= 0.159 mol of C₆H₆
Molar mass of C₆H₆ = 12 x 6 + 1 x 6 =78 g /mol
Mass of C₆H₆ =Molar mass x Number of moles
= 78 g / mol x 0.159 mol
= 12.41 g
Answer:
(i) Cl₂ is a limiting reactant
(ii) The amount of excess reactant = 4.8 g
Explanation:
Br₂(g) + Cl₂(g) → 2 BrCl(g) ---------------------------(i)
Calculation of no. of moles
Using mole ratio method to find the limiting reactant and Excess reactant.
So is a limiting reactant and Br₂ is excess reactant.
The amount of excess reactant = 0.18 - 0.15 = 0.03 mole = 4.8 g