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mash [69]
3 years ago
15

Calculate the average bond order for a p−o bond (such as the one shown in blue) in a phosphate ion. express your answer numerica

lly as a decimal or improper fraction.
Chemistry
1 answer:
PtichkaEL [24]3 years ago
5 0
<span>Answer: 1/4 is the average bond order for a pâ’o bond (such as the one shown in blue) in a phosphate ion.</span>
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The answer is C

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Ionic compounds involve a (share, tranfer) of electrons and typically involve atoms that have (Large, similar, very different) e
Juliette [100K]

Answer:

2 Transfer; very different

Explanation:

Ionic compound are compound that are formed from transfer of electron. The cations donate the electron(s) while the anion receive the electron(s). The compound possess a positively charged end and a negatively charge end. Example of ionic compound is NaCl . The sodium donates one electron to the chlorine  to fulfill the octet rule. The sodium atom becomes positively charged  as it donate electron to the chlorine atom. The chlorine atom becomes negatively charged as it receive electron from Sodium atom.

The atoms that are involve in forming ionic compound have very different electronegativity . Electronegativity  is the measure of the ability of an atom to attract a bond pair of electron. For example the NaCl compound, the two atom has verse differences in the electronegativity. Cl atom is far more electronegative than Sodium atom.

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3 years ago
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igor_vitrenko [27]

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1.25 Quiz: Impacts of Humans
vekshin1
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JWL 3.R 1.096776 x 107 m) L) 384.6 nm C) 683.8 nm D) 1282 nm E) &gt;1500 nm Ans: D According to the Rydberg equation, the line w
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Answer:

91.2 nm

Explanation:

The Rydberg equation is given by the formula

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where

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and n₁ and n₂ are the energy levels of the transion.

We can see from this equation that the wavelength is inversely proportional to the difference of the squares of the inverse of the quantum numbers n₁ and n₂. It follows then that the smallest wavelength will be given when the the transitions are between the greatest separation between n₁ and n₂ whicg occurs when n1= 1 and n₂= ∞ , that is the greater the separation in energy levels the shorter the wavelength.

Substituting for n₁ and n₂ and solving for λ :

  1/λ = 1.0974 x 10⁷ m⁻¹ x ( 1/1² -1/ ∞²)  =  1.0974 x 10⁷ m⁻¹ x ( 1/1² - 0) =

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