As soon as I read this, the words "law of cosines" popped into my head. I don't have a good intuitive feeling for the law of cosines, but I went and looked it up (you probably could have done that), and I found that it's exactly what you need for this problem.
The "law of cosines" relates the lengths of the sides of any triangle to the cosine of one of its angles ... just what we need, since we know all the sides, and we want to find one of the angles.
To find angle-B, the law of cosines says
b² = a² + c² - 2 a c cosine(B)
B = angle-B b = the side opposite angle-B = 1.4 a, c = the other 2 sides = 1 and 1.9
(1.4)² = (1)² + (1.9)² - (2 x 1 x 1.9) cos(B)
1.96 = (1) + (3.61) - (3.8) cos(B)
Add 3.8 cos(B) from each side:
1.96 + 3.8 cos(B) = 4.61
Subtract 1.96 from each side:
3.8 cos(B) = 2.65
Divide each side by 3.8 :
cos(B) = 0.69737 (rounded)
Whipping out the trusty calculator: B = the angle whose cosine is 0.69737
= 45.784° .
Now, for the first time, I'll take a deep breath, then hold it while I look back at the question and see whether this is anywhere near one of the choices ...
By gosh ! Choice 'B' is 45.8° ! yay ! I'll bet that's it !
You would start by adding the 18 to the 2 to give you 20. then you would subtract x from the 6x to give you 5x. then your equation should be 5x=20, then you divide 20 by 5 and that give you 4. So x would equal 4. x=4
