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Alisiya [41]
3 years ago
9

If an alkaline battery produces a cell potential of 1.46 v, what is the value of δgcell? the half-reactions in alkaline batterie

s are: $$zno(s)+h2​o(l)+2e− zn(s)+2oh−(aq)
Chemistry
1 answer:
Gala2k [10]3 years ago
4 0
The formula we're gonna use for this problem is written below:

ΔG°= nFE°
where
n is number of mol electrons displaced in the reaction
F is Faraday's constant = 96,500 C/mol e
E° is the standard emf

ΔG° = (2)(96,500)(1.46) = <em>281,780 Joules</em>
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The reaction involved in present case is:

Net Reaction: Ca   +    1/2 O2    →         CaO. ..................(1)

In terms of oxidation and reduction, the reaction can be shown at

Oxidation: Ca     →       Ca2+      +       2e- .................(2)
Reduction: 1/2O2    +   2e-      →      O2-...................(3)

From, reaction 1 it can be seen that 1 mol of Ca reacts with 1/2 mol of O2 to form 1 mol of CaO.

From, reaction 2 it can be seen that 1 mol of Ca, generates 2 mol of e-.

Thus, when 1/2 mol of Ca is used in reaction, it will lose 1 mol of electrons.
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Molar Mass of Calcium carbonate:-

\\ \sf\longmapsto CaCO_3

\\ \sf\longmapsto 40u+12u+3(16u)

\\ \sf\longmapsto 52u+48u

\\ \sf\longmapsto 100u

\\ \sf\longmapsto 100g/mol

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\boxed{\sf No\:of\;moles=\dfrac{Given\:Mass}{Molar\:Mass}}

\\ \sf\longmapsto No\:of\;moles=\dfrac{10}{100}

\\ \sf\longmapsto No\:of\:moles=0.1mol

Now

\boxed{\sf No\:of\:molecules=No\;of\:moles\times Avagadro\: No}

\\ \sf\longmapsto 0.1\times 6.023\times 10^{23}

\\ \sf\longmapsto 6.023\times 10^{22}molecules

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