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3 years ago

14

2. An object is moving with an initial velocity of 12 m/s. It accelerates at a rate of 1.5 m/s^2 over a distance of 40 m. What i

s its new velocity?

1 answer:

nikklg [1K]3 years ago

4 0

Answer:

16.2 m/s

Explanation:

2ad=Vf^2-Vi^2

2 (1.5) (40) = Vf^2 -(12)^2

Vf= 16.2 m/s

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The sound power the person generated is $2.313 \times 10^{-5} \ W$ .

<h3>Area of the sound wave</h3>

The area of the sound wave is calculated as follows;

$A = 4\pi r^2\\\\A = 4 \pi \times (2)^2\\\\A = 50.272 \ m^2$

<h3>Power generated</h3>

The sound power the person generated is calculated as follows;

$P = I A\\\\P = 4.6\times 10^{-7} \ W/m^2 \ \ \times \ \ 50.272 \ m^2\\\\P = 2.313 \times 10^{-5} \ W$

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In other words, the sound intensity decreases as inversely proportional to the squared of the distance. i.e. $\frac{1}{r^2}$

In the context when the distance was 3 m, the intensity of the sound was = $\frac{1}{9}$

But when the distance became 6 cm or 0.06 m, the sound intensity decreases by = $\frac{1}{0.06^2}$

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