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Vitek1552 [10]
3 years ago
14

A railroad car with mass m is moving with an initial velocity v when it collides and connects with a second railroad car with a

mass of 3m, which is initially at rest. How do the speed and momentum of the connected car system compare with those of the car with mass m before the collision
Physics
1 answer:
inessss [21]3 years ago
7 0

Answer:

Same momentum but speed is reduced 4 times.

Explanation:

According to the law of momentum conservation, the total momentum of the system before and after the collision is the same

Before the collision, the bigger car is at rest, only the 1st car of mass m is moving at speed v

p = mv

After the collision, both cars are connected and moving at speed V

P = (m + 3m)V = 4mV

These 2 momentum are equal

p = P

mv = 4mV

V = v/4

So after the collision, they have the same momentum but the speed decreased 4 times

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<span>The width of the physical spectrum is shorter than that of the electromagnetic spectrum. The visible spectrum is the light that can be seen with the human eye, which we see as the colors red, orange, yellow, green, blue, indigo, and violet or ROY G. BIV. However, there are more wavelengths that can be seen beyond that, which are apart of the electromagnetic spectrum. For example, the UV rays, microwaves, and Gamma Rays cannot be seen by the human eye. Therefore, the electromagnetic spectrum is longer than the visible spectrum because there is so much more that humans can not see. The visible spectrum is only 400-750nm. The electromagnetic spectrum is 10 to the -14 to 10 to the 4 meters.</span>
5 0
3 years ago
A police car with its 300-Hz siren is moving toward a warehouse at 30 m/s, intending to crash through the door. The sound bounce
Lady bird [3.3K]

Answer: The frequency heard will be f = 275.675Hz

Explanation: When an object emitting sound is moving, it occurs a phenomenon called Doppler shift or Doppler effect. What happens is that the sound gets higher when the moving object comes closer the observer and becomes lower after it passes, This change is due to the quantity of waves that passes through an area in an unit of time.

The formula to calculate the Doppler effect is as follows

f = (\frac{c}{c+Vs}) · f₀

f is the observed frequency;

c is the speed of sound;

Vs is velocity of the source;

f₀ is the emitted frequency of source;

Substituting and calculating,

f = \frac{340}{340+30} · 300

f = 275.675 Hz

Thus, the frequency heard by the police officer is 275.675Hz.

8 0
3 years ago
__________ is when a person becomes less sensitive to a drug. A. Tolerance B. Craving C. Addiction D. Dependence
Luden [163]
A) Tolerance

Tolerance is developed after using a drug repeatedly, so the body adapts to it. Because of that, people who develop a tolerance would then need to use more of that drug to get the same effect.
4 0
3 years ago
An object, when pushed with a net force F, has an acceleration of 4 m/s . Now twice the force is applied to an object that has f
hjlf

Answer:

B. 2 m/s

B. Acceleration = 4.05 m/s² and Tension = 297.5 N.

Explanation:

A force is applied on a mass m whose acceleration is 4 m/s

Force = mass × acceleration

a = F/m = 4 m/s

4 m/s = F/m

F = 4 m/s (m)

If  Force of 2F is applied on a mass of 4m ; it acceleration is as follows:

2F/4 m = F/ 2m

4m/s (m) / 2m = 2 m/s

a = 2 m/s

2.

Given that

mass m_1 = 30 kg

mass m_2 = 50 kg

\mu = 0.1

From the question; we can arrive at two cases;

That :

m_{2} a _ \ {net} }= m_2g - T   ----- equation (1)

m_{1} a _ \ {net} }=  T - mg sin \theta  - F ---- equation (2)

50 a = 50 g - T

30 a = T - 30 g sin 30 - 4 × 30 g cos 30

By summation

80 a =[ 50  - 30 * \frac{1}{2} - 0.1 *30* \frac{\sqrt{3}}{2}]g

80 a = 32. 4 × 10 m/s ²  (using g as 10m/s²)

80 a = 324 m/s ²

a = 324/80

a = 4.05 m/s²

From equation , replace a with 4.05

50 × 4.05 = 50 × 10 - T

T = 500 -202.5

T =297.5 N

8 0
3 years ago
Mechanical energy is the sum of ________ energy and potential energy.apex
crimeas [40]
Mechanical energy is the sum of kinetic energy and potential energy
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3 years ago
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