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mars1129 [50]
3 years ago
10

speed is the ratio of the distance an object moves to a. the direction the object moves. b. the amount of time needed to travel

the distance. c. the motion of the object. d. the displacement of the object.
Physics
2 answers:
Dennis_Churaev [7]3 years ago
5 0
It is the ratio of distance an object moves to the amount of time needed to travel the distance. Option b.
quester [9]3 years ago
4 0

Option (b) is correct. Speed is the ratio of the distance an object moves to <u>the amount of time needed to travel the distance. </u>

<u> </u>

Further Explanation:

The speed of a body is defined as the rate of the distance covered by the body. It means that the speed is the measure of the amount of distance covered by a body in a particular interval of time.

The mathematical expression for the velocity of a body is given as.

speed = \dfrac{{distance}}{{time}}  

The above mathematical expression shows that the speed of a body is the ratio of the distance covered by the body to the amount of time taken by the body to cover the particular distance.

Learn More:

  1. Choose the 200 kg refrigerator. Set the applied force to 400 n (to the right). Be sure friction is turned off. What is the net force acting on the refrigerator brainly.com/question/4033012
  2. Which of the following is not a component of a lever brainly.com/question/1073452
  3. The amount of kinetic energy an object has depends on its brainly.com/question/137098

Answer Details:

Grade: High School

Chapter: Speed and distance

Subject: Physics

Keywords:  Speed, ratio, distance, displacement, rate of distance, covered by body, time taken, mathematical expression, an object.

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Answer:7 cm/s

Explanation:

Given

Particle move along curve

y=\sqrt{1+x^3}

As it reaches the (2,3) its y coordinate is increasing at 14 cm/s

Differentiating y w.r.t time

\frac{\mathrm{d} y}{\mathrm{d} t}=\frac{3x^2}{2\sqrt{1+x^3}}\times \frac{\mathrm{d} x}{\mathrm{d} t}

Now at (2,3)

\frac{\mathrm{d} y}{\mathrm{d} t}=\frac{3\cdot 2^2}{2\sqrt{1+2^3}}\times \frac{\mathrm{d} x}{\mathrm{d} t}

14=\frac{3\times 4}{2\times \sqrt{9}}\times \frac{\mathrm{d} x}{\mathrm{d} t}

\frac{\mathrm{d} x}{\mathrm{d} t}=7 cm/s

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2 years ago
A contestant in a winter games event pulls a 36.0 kg block of ice across a frozen lake with a rope over his shoulder as shown in
Novay_Z [31]

(a) The minimum force F he must exert to get the block moving is 38.9 N.

(b) The acceleration of the block is 0.79 m/s².

<h3>Minimum force to be applied </h3>

The minimum force F he must exert to get the block moving is calculated as follows;

Fcosθ = μ(s)Fₙ

Fcosθ = μ(s)mg

where;

  • μ(s) is coefficient of static friction
  • m is mass of the block
  • g is acceleration due to gravity

F = [0.1(36)(9.8)] / [(cos(25)]

F = 38.9 N

<h3>Acceleration of the block</h3>

F(net) = 38.9 - (0.03 x 36 x 9.8) = 28.32

a = F(net)/m

a = 28.32/36

a = 0.79 m/s²

Thus, the minimum force F he must exert to get the block moving is 38.9 N.

The acceleration of the block is 0.79 m/s².

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2 years ago
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Explanation:

SUPONIENDO QUE LA ACELERACIÓN DE LA GRAVEDAD ES 9.80 m/s^{2}

USANDO LA SEGUNDA LEY DE NEWTON:

<em>m</em> = 80.0 N/9.80 m/s^{2} = 8.16 kg

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Answer:

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