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Keith_Richards [23]
3 years ago
15

A rectangular solid made of carbon has sides of lengths 1.0 cm, 2.0 cm, and 4.0 cm, lying along the x, y, and z axes, respective

ly. Wires are connected to the faces and the resistance of the block is measured. The resistance will be the least when the wires are hooked up so that current flows in
Physics
1 answer:
sammy [17]3 years ago
8 0

Answer:

The correct answer is in the x-axis direction, where the distance travelled is 1.0 cm and the surface is 8 cm^{2}.

Explanation:

The electrical resistance is lower when the contact surface is larger and the length is shorter.

An electrical resistance is an opposition to the flow of electric current through a conductor. For a given conductor, the resistance is given by the following formula:

R = ρ * \frac{l}{S}

Where:

R: Electrical resistance.

ρ: Resistivity of the material.

l: Length.

S: Surface of the conductor.

Thus, the direction in which the electrical resistance is lower is when the distance is minimum and the area is greater.

Have a nice day!

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Two long wires hang vertically. Wire 1 carries an upward current of 1.50 A . Wire 2,20.0cm to the right of wire 1, carries a dow
Inessa [10]

The magnitude of the current in wire 3  is 2.4 A and in a direction pointing in the downward direction.

  • The force per unit length between two parallel thin current-carrying I_1 and I_2  wires at distance ' r ' is given by  f=\frac{u_0I_1I_2}{2\pi r}   ....(1) .
  • If the current is flowing in both wires in the same direction, and  the force between them will be the attractive force and if the current is flowing in opposite direction in wires then the force between them will be the repulsive force.

A schematic of the information provided in the question can be seen in the image attached below.

From the image, force on wire 2 due to wire 1 = force on wire 2 due to wire 3

F_2_1=F_2_3

Using equation (1) , we get

\frac{u_0I_2I_1}{0.2} =\frac{u_0I_2I_3}{0.32} \\\\\frac{I_1}{0.2} =\frac{I_3}{0.32} \\\\\frac{1.50}{0.2} =\frac{I_3}{0.32} \\\\0.48=0.2I_3\\\\I_3=2.4A

I₃ = 2.4 A and the current is pointing in the downward direction

Learn more about the magnitude and direction of forces here:

brainly.com/question/14879801?referrer=searchResults

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5 0
1 year ago
The recommended adult dose of elixophyllin, a drug used to treat asthma, is 6.00 mg/kg of body mass. calculate the dose in milli
andreev551 [17]

For a 166-lb person, a dose of 452 milligrams is prescribed to treat asthma.

<h3>How would you define asthma?</h3>

Lung damage is a side effect of asthma. Repeated episodes of coughing, dyspnea, chest tightness, and wheezing are also brought on by it. By taking medication and avoiding the triggers that can set off an attack, asthma can be managed. Outdoor allergens, such as pollen from grass, trees, and weeds, are common asthma triggers. Different allergens and irritants might function as triggers for different people. Dust mites, cockroaches, mold, and pet dander are examples of indoor allergies. Air irritants like smoke, chemical fumes, and powerful scents.

Mass = 166 lb×(453.59 g/1 lb)×(1kg/1000g)=75.30 kg

Dose = 75.30 kg ×(6.00 mg/1 kg)=452 mg

Elixophyllin has a 452 mg dose for a 166 lb person with asthma.

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8 0
1 year ago
Please help me with this
Firlakuza [10]

Answer:

can't see anything sorry can't help

7 0
2 years ago
Read 2 more answers
You have a 10 volt parallel circuit, with 2 resistors on it. What is the voltage across the first resistor? Across the second?
zheka24 [161]
What is the value of the resistors?  There are many types of resistors with different values for how much resistance they provide

Edit: My bad.  Where are the resistors located
3 0
3 years ago
Read 2 more answers
A projectile is shot at an angle 45 degrees to the horizontalnear the surface of the earth but in the absence of air resistance.
ivann1987 [24]

Answer:

v₂ = 176.24 m/s

Explanation:

given,

angle of projectile = 45°

speed = v₁ = 150 m/s

for second trail

speed = v₂ = ?

angle of projectile = 37°

maximum height attained formula,

H_{max}= \dfrac{v^2 sin^2(\theta)}{g}

now,

H_{max}= \dfrac{v_1^2 sin^2(\theta_1)}{g}

H_{max}= \dfrac{v_2^2 sin^2(\theta_2)}{g}

now, equating both the equations

\dfrac{v_2^2}{v_1^2}=\dfrac{sin^2(\theta_1)}{sin^2(\theta_2)}

\dfrac{v_2^2}{150^2}=\dfrac{sin^2(45^0)}{sin^2(37^0)}

   v₂² = 31061.79

   v₂ = 176.24 m/s

velocity of projectile would be equal to v₂ = 176.24 m/s

8 0
3 years ago
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