Let's simplify step-by-step.
<span><span><span><span>2b</span>+<span>3r</span></span>+<span>4b</span></span>+r</span>
Combine Like Terms:
<span>=<span><span><span><span>2b</span>+<span>3r</span></span>+<span>4b</span></span>+r
</span></span><span>=<span><span>(<span><span>2b</span>+<span>4b</span></span>)</span>+<span>(<span><span>3r</span>+r</span>)
</span></span></span><span>=<span><span>6b</span>+<span>4r</span></span></span>
Answer:<span>=<span><span>6b</span>+<span>4<span>r</span></span></span></span>
Answer:
The percentle for Abby's score was the 89.62nd percentile.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation(which is the square root of the variance)
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Abby's mom score:
93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the scores was 9604.
93rd percentile. X when Z has a pvalue of 0.93. So X when Z = 1.476.

So




Abby's score
She scored 648.

So



has a pvalue of 0.8962.
The percentle for Abby's score was the 89.62nd percentile.
Answer:
+213 is the correct answer
Answer:
7×3
Step-by-step explanation:
option b
i hope it is helpful for you