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2 years ago

Which 2 or 3 are they pls help

Mathematics

2 answers:

True [87]2 years ago

7 0

The answer is B.

z x 1 = z

z x 0.37 = 0.37z

= z + 0.37z

Harlamova29_29 [7]2 years ago

7 0

The answer is B I think!

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Y-1.6=8.76 what is y

Verizon [17]

Answer:

y = 10.36

Step-by-step explanation:

y - 1.6 = 8.76

add 1.6 to both sides

y - 1.6 + 1.6 = 8.76 + 1.6

y = 10.36

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2 years ago

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Lelu [443]

$27.((3^{3})^{-1} = 27.(27)^{-1} = 27 .\frac{1}{27} = 1$

This is because $3^{3} = 3 x 3 x 3 = 9 x 3 = 27$

And $(27)^{-1} means \frac{1}{27}$

For this reason, $27. (27)^{-1} = 1$

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3 years ago

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Given x=-3, y=6, and z=-4 -15+(-x)+y= Thank you for your help!

lesya692 [45]

Solution:

Given, x=-3, y=6, and z=4

Putting these values in the given equation:

-15+(-x)+y

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3 years ago

What is the probability that another student has the same birthday as you?

Flura [38]

There are 365 days in a year. So the answer is

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3 years ago

A car is being driven at a rate of 40 ft/sec when the brakes are applied. The car decelerates at a constant rate of 10 ft/sec2.

IRISSAK [1]

Answer:

80 feet

Step-by-step explanation:

Given:

Initial speed of the car ( $v_0$ ) = 40 ft/sec

Deceleration of the car ( $\frac{dv}{dt}$ ) = -10 ft/sec²

Final speed of the car ( $v_x$ ) = 0 ft/sec

Let the distance traveled by the car be 'x' at any time 't'. Let 'v' be the velocity at any time 't'.

Now, deceleration means rate of decrease of velocity.

So, $\frac{dv}{dt}=-10\ ft/sec^2$

Negative sign means the velocity is decreasing with time.

Now, $\frac{dv}{dt}=\frac{dv}{dx}(\frac{dx}{dt})$ using chain rule of differentiation. Therefore,

$\frac{dv}{dx}\cdot\frac{dx}{dt}= -10\\\\But\ \frac{dx}{dt}=v.\ So,\\\\v\frac{dv}{dx}=-10\\\\vdv=-10dx$

Integrating both sides under the limit 40 to 0 for 'v' and 0 to 'x' for 'x'. This gives,

$\int\limits^0_{40} {v} \, dv=\int\limits^x_0 {-10} \, dx\\\\\left [ \frac{v^2}{2} \right ]_{40}^{0}=-10x\\\\-10x=\frac{0}{2}-\frac{1600}{2}\\\\10x=800\\\\x=\frac{800}{10}=80\ ft$

Therefore, the car travels a distance of 80 feet before stopping.

4 0

3 years ago