The radius of the track in the circular motion is 0.164 mm.
<h3>Magnetic force of the of charge</h3>
The magnetic force of the charge is calculated as follows;
F = qvB
<h3>Centripetal force of the charge</h3>
The centripetal force experienced by the charge is calculated as follows;
<h3>The magnetic force is equal to the centripetal force</h3>
<h3>The radius of the track</h3>
The radius of the track is calculated as follows;
Thus, the radius of the track in the circular motion is 0.164 mm.
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Answer:
= 0.417 m/s
Explanation:
Momentum before throwing the rock: m*V = 95.0 kg * 0.460 m/s
= 44.27 N*s
A) man throws the rock forward
mass of rock m1 = 0.310 kg
V1 = 15.5 m/s, in the same direction of the sled with the man
sled and man:
m2 = 95 kg - 0.310 kg = 94.69 kg
v2 = ?
Conservation of momentum:
momentum before throw = momentum after throw
44.27N*s = 0.310kg * 15.5m/s + 94.69kg*v2
⇒ v2 = [44.27 N*s - 0.310 * 15.5N*s ] / 94.69 kg
= 0.417 m/s
The velocity is 1100 kilometers per hour
It is an example of balanced force.
hope this helps. good luck
