The cliff is 2042 ft away.
We know that the speed of sound in air is directly proportional to the absolute temperature.
First convert the Fahrenheit temperature to Celsius;
°C = 5/9(44.5 - 32)
°C = 6.9 °C
Applying the formula;
V1/V2 = √T1/T2
Where; V1 = velocity of sound in air at 0°C
V2 = Velocity of sound in air at 6.9 °C
1087/V2 = √273/279.9
V2= 1101 ft/s
Given that; V = 2s/t
Where s is the distance of the cliff
t is the time taken
1101 ft/s = 2s/3.71 s
s = 1101 ft/s × 3.71 s/2
s = 2042 ft
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The coefficient of static friction between the puck and the surface.
In fact, that coefficient describes exactly how "hard" it is to cause the puck to start moving, if it starts from an idle condition.
Answer:
My best guess would be B due to the fact of friction in a simple machine
The angular speed of the minute hand is the ratio between the angle covered and the time taken. The angle covered by the minute hand is
, while the time needed is
, so the angular speed is
And the tangential speed is given by
