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Ronch [10]
3 years ago
10

In a reaction vessel of 10.0 I, heat 9.00 g of water so that it partially decomposes. In the equilibrium mixture, 0.250 mol of w

ater vapor is then still present. (a) Calculate the equilibrium constant K under the given conditions. (b) How is the equilibrium of the reaction affected by i. 1° reduction in volume ii. 2° increase in temperature?​
Chemistry
1 answer:
MatroZZZ [7]3 years ago
7 0

Answer:

help

Explanation:

How much carbon will turn into carbon 14 every year?

Science

Please help asap

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If carbon has the electron configuration of (2,4) what would the electron configuration of the element to the right of it on the
Svetllana [295]

Answer:

2,5

Explanation:

When move from left to right in periodic table atomic number increases. So element to the right of carbon has one electron more than carbon therefore it's electronic configuration would be 2,5

3 0
3 years ago
Assuming that the bath contains 250.0 g of water and that the calorimeter itself absorbs a negligible amount of heat, calculate
Anvisha [2.4K]

Answer:

-3272     kJ/mol

Explanation:

Given and known facts

Mass of Benzene = 0.187 grams

Mass of water = 250 grams

Standard heat capacity of water = 4.18 J/g∙°C

Change in temperature ΔT = 7.48°C

Heat

=250 * 4.18 * 7.48\\=7816.6 \\=7.82

Heat released by benzine is - 7.82 kJ

Now, we know that

0.187 grams of benzene release = -7.82  kJ heat

So, 1 g benzine releases

\frac{ -7.82 }{0.187}\\= -41.8

kJ/g

0.187 * \frac{1}{78.108}=0.00239 mol C6H6

Heat released

= \frac{-7.82}{ 0.00239}

=-3272     kJ/mol

4 0
3 years ago
Label the following changes as Physical or
Leno4ka [110]

Answer:

17

Two clear liquids mix and form a

white solid

18.chemical

A pot of water begins to

boil

19.Physical

the rest im usure on.

5 0
3 years ago
If 1 kg of fuel is used in the above fusion reaction (2 1H + 3 1H--> 4 2He+1 0N) , the resulting helium has a mass of 0.993 k
enot [183]
Δmc
2

For one reaction:
Mass Defect =Δm
=2(m
H
​
)−m
He
​
−m
n
​

=2(2.015)−3.017−1.009
=0.004 amu
1 amu=931.5 MeV/c
2

Hence,
E=0.004×931.5 MeV=3.724 MeV
E=3.726×1.6×10
−13
J=5.96×10
−13
J

For 1 kg of Deuterium available,
moles=
2g
1000g
​
=500
N=500N
A
​
=3.01×10
26

Energy released =
2
N
​
×5.95×10
−13
J
=8.95×10
13
6 0
2 years ago
A substance is made up of slow-moving particles that have very little space between them. Based on this information, what can mo
spin [16.1K]

Answer:

o

Explanation:

it is not a gas because the particles do not move freely it may be a liquid or a solid partly and mostly liquidized.

8 0
3 years ago
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