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vladimir1956 [14]
2 years ago
7

If Cade shoots 318 free throw baskets in 4 hours, about how many can he shoot in 7 hours?

Mathematics
2 answers:
yanalaym [24]2 years ago
6 0

Answer:

556.5 baskets

Step-by-step explanation:

Write a proportion to solve

\frac{318}{4hours} = \frac{x}{7 hours}

Use the cross products

318 × 7 = 4 × x

2226 = 4x

Divide both sides by 4

\frac{2226}{4x} = \frac{4x}{4}

556.5 baskets is your answer!

dusya [7]2 years ago
3 0

Answer:

556.5 baskets

Step-by-step explanation:

We can write a proportion to solve

318 baskets     x baskets

----------------- = ----------------

4 hours              7 hours

Using cross products

318* 7 = 4 *x

2226 = 4x

Divide each side by 4

2226/4 = 4x/4

556.5 baskets

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Answer:

Step-by-step explanation:

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1 year ago
How do you solve 2x+4=7
marissa [1.9K]
2x+4=7  subtract 4 from both sides

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3 years ago
If cos=3/5, then tan=
Juliette [100K]
This is a 3-4-5 triangle.

Remember, 
SOH-CAH-TOA

S(ine) =  O(pposite)/H(ypotenuse)
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T(angent) = O(pposite)/A(djacent)

In Cosine, the adjacent = 3, and the Hypotenuse = 5

Hypotenuse is the longest side. 

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6 0
3 years ago
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The probability that a randomly selected box of a certain type of cereal has a particular prize is 0.20.
MatroZZZ [7]

Answer:

a) the probability is 0.0734 (7.34%)

b) the probability is 0.7382 (73.82%)

c) 10 boxes

Step-by-step explanation:

Since each box is independent of the others and defining the random variable X= number of boxes of cereal purchased without prices until having 2 prices , then X has a negative binomial distribution . Thus

P(X=k)= C(k+r-1,k)*p^k *(1-p)^r

where

p= probability to not obtain a price when a box is purchased = 1- 0.2 = 0.8

C ( ) = combinations

k = number of boxes without prices

r= number of boxes with prices=2

P(X=k) = probability of purchasing k boxes without prices until obtaining r boxes with prices

a) for k= 8 - r = 6

P(X=6)= C(7,6)*0.8^6*0.2^2 = 7*0.8^6*0.2^2 = 0.0734 (7.34%)

b) for k≥9-2=7

P(X≥7) = 1- P(X<7)= 1- Fn(X=7)

where Fn(X) is the cumulative negative binomial distribution. We can calculate it through its relationship with the cumulative binomial distribution Fb(X) that is easily found in tables :

Fn(k=7,r=2,p=0.8) = Fb(k=7,n=k+r=9,p=0.8) = 0.2618

thus

P(X≥7) = 1- P(X<7)= 1- Fn(X=7) = 1-  0.2618 = 0.7382 (73.82%)

c) the expected value E(X) for a negative binomial distribution is

E(X)= p*r/(1-p) = 0.8*2/0.2 = 8 boxes that do not contain prices

thus

n=k+r = 8 + 2 = 10 boxes

6 0
3 years ago
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