The mass of an object does not affect its speed along an inclined plane, presuming that the object's mass does not prevent it from moving altogether. Only the force of gravity, the angle of the incline and the coefficient of friction influence the object's speed.
Answer:
The thing where the 2 poles sit
Explanation:
Answer:
1.02 m/s²
Explanation:
The following data were obtained from the question:
Initial velocity (u) = 0 m/s
Final velocity (v) = 6.6 m/s
Time (t) = 6.5 s
Acceleration (a) =.?
Acceleration can simply be defined as the change of velocity with time. Mathematically, it can be expressed as:
a = (v – u) / t
Where:
a is the acceleration.
v is the final velocity.
u is the initial velocity.
t is the time.
With the above formula, we can obtain the acceleration of the car as follow:
Initial velocity (u) = 0 m/s
Final velocity (v) = 6.6 m/s
Time (t) = 6.5 s
Acceleration (a) =.?
a = (v – u) / t
a = (6.6 – 0) / 6.5
a = 6.6 / 6.5
a = 1.02 m/s²
Therefore, the acceleration of the car is 1.02 m/s²
Answer:
d. -y direction
Explanation:
Given that
m₁=0.145 kg, u₁=2.1 j m/s
m₂= 0.0570 kg , u₂ = -8.8 j m/s
We know that linear momentum is the product of mass and velocity
P= Mass x velocity
Therefore the total linear momentum P
P= m₁u₁+ m₂u₂
Now by putting the values
P = 0.145 x ( 2.1 j) + 0.057 ( - 8.8 j) kg.m/s
P =0.3045 j - 0.5016 j kg.m/s
P= - 0.1971 j kg.m/s
P= 0.1971 (- j) kg.m/s
So we can say that the direction of the liner momentum of the system will be in the negative y -direction.
d. -y direction
Assuming the deer's acceleration was constant, we have
where is the deer's total displacement, are the deer's final and initial velocities, and is time. Then