The magnitude of the electric field at a point inside the sphere that lies 8.0 cm from the center is 4.5 ×
Given
Radius = 20 cm
Electric field at a point inside the sphere that lies 8.0 cm from the center.
ρ = 1.5 x 10-6 c/m3
E (r) = ρr / 3εο = 1.5 × × 8 × / 3 × 8.85 × = 4.5 ×
The physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them, is known as an electric field (also referred to as an E-field[1]). [2] It also describes the physical field of a system of charged particles. [3] Electric charges and time-varying electric currents are the basis of electric fields. A manifestation of the electromagnetic field, one of the four fundamental interactions (sometimes known as forces) of nature, is electromagnetic fields, which also include electric and magnetic fields.
Electric fields play a significant role in many branches of physics and are used in electrical engineering. For instance, in atomic physics and chemistry, the electric field acts as the attracting force that holds the atomic nucleus and electrons together in atoms. Additionally, it is the driving force for atoms' chemical bonds.
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Answer:
Explanation:
Given that
We know that from continuity equation
So
Now from energy equation
Q=6.17 x 0.08
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Skeletal muscles must have help from the bone to be able to move.
To solve this problem we will apply the definitions given in Newtonian theory about the Force of gravity, and the Force caused by weight. Both will be defined below, and in equal equilibrium condition to clear the variable concerning acceleration due to gravity. Finally, with the values provided in the statement, it will be replaced.
The equation for the gravitational force between the Earth and the object on the surface of the Earth is
Where,
G = Universal gravitational constant
= Mass of Earth
= Distance between object and center of earth
= Mass of Object
The equation for the gravitational pulling force on the object due to gravitational acceleration is
Equation the two expression we have
This the acceleration due to gravity which is composite constant.
Replacing with our values we have then
The value of composite constant is . Here, the composite constant is nothing but the acceleration due to gravity which is constant always.