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xenn [34]
3 years ago
8

A baseball with mass 0.145 kg is moving in the+y direction with a speed of 2.10m/s, and a tennis ball with mass 0.0570 kg is mov

ing in the-y direction with a speed of 8.80m/s. What is the magnitude of the total momentum of the systemconsisting of the two balls? What is the direction of the total momentum of thesystem?
a. +x direction
b. +ydirection
c. -x direction
d. -y direction
Physics
1 answer:
Artist 52 [7]3 years ago
7 0

Answer:

d. -y direction

Explanation:

Given that

m₁=0.145 kg, u₁=2.1 j m/s

m₂= 0.0570 kg ,  u₂ = -8.8 j m/s

We know that linear momentum is the product of mass and velocity

P= Mass x velocity

Therefore the total linear momentum P

P= m₁u₁+ m₂u₂

Now by putting the values

P = 0.145 x ( 2.1 j) + 0.057 ( - 8.8 j)  kg.m/s

P =0.3045 j - 0.5016 j   kg.m/s

P=  - 0.1971 j kg.m/s

P= 0.1971 (- j) kg.m/s

So we can say that the direction of the liner momentum of the system will be in the negative y -direction.

d. -y direction

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C

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It has to travel 600 light years before we would be able to observe the explosion.

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Time  =        (distance) / (speed)

Time  =  (150 x 10⁹ m) / (3 x 10⁸ m/s) =

                           50 x 10¹ sec  = 

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4 years ago
How do I solve this problem
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3 years ago
A truck is hauling a 300-kg log out of a ditch using a winch attached to the back of the truck. Knowing the winch applies a cons
torisob [31]

Answer:

0.1 s

Explanation:

The net force on the log is F - f = ma where F = force due to winch = 2850 N, f = kinetic frictional force = μmg where μ = coefficient of kinetic friction between log and ground = 0.45, m = mass of log = 300 kg and g = acceleration due to gravity = 9.8 m/s² and a = acceleration of log

So F - f = ma

F - μmg = ma

F/m - μg = a

So, substituting the values of the variables into the equation, we have

a = F/m - μg

a = 2850 N/300 kg - 0.45 × 9.8 m/s²

a = 9.5 m/s² - 4.41 m/s²

a = 5.09 m/s²

Since acceleration, a = (v - u)/t where u = initial velocity of log = 0 m/s (since it was a rest before being pulled out of the ditch), v = final velocity of log = 0.5 m/s and t = time taken for the log to reach a speed of 0.5 m/s.

So, making t subject of the formula, we have

t = (v - u)/a

substituting the values of the variables into the equation, we have

t = (v - u)/a

t = (0.5 m/s - 0 m/s)/5.09 m/s²

t = 0.5 m/s ÷ 5.09 m/s²

t = 0.098 s

t ≅ 0.1 s

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3 years ago
Calculate the magnitude of the gravitational force exerted by the Moon on a 79 kg human standing on the surface of the Moon. (Th
Luden [163]

Answer:

F= 134.92 N

Explanation:

Given that

The mass of the moon ,M = 7.4 x 10²² kg

The mass of the man ,m = 79 kg

The radius ,R= 1.7 x 10⁶ m

The force exerted by moon is given as

F=G\dfrac{Mm}{R^2}

Now by putting the values in the above equation we get

F=6.67\times 10^{-11}\times \dfrac{79\times 7.4\times 10^{22}}{(1.7\times 10^6)^2}\ N\\F=134.92 N

Therefore the force will be 134.92 N.

F= 134.92 N

8 0
4 years ago
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