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2 years ago

A progressive wave is represented by the following equation :

Physics

1 answer:

Ilia_Sergeevich [38]2 years ago

7 0

Explanation:

I. Direction - Towards the negative x axis since there's a '+' sign b/n π/4 & X

II. y = Asin(wt + kx)

k = 2π/ለ = 1

ለ = 2πcm = 6.29cm or 6.29×10^-2m in meter

i suggest using the one in cm.

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A horse runs a distance of 240 m in 20 s. Which of the following is a scalar quantity that can be determined from this

mariarad [96]

Explanation:

distance and time both are scaler quantity

6 0

3 years ago

A gas sample is held at constant pressure. The gas occupies 3.62 L of volume when the temperature is 21.6°C. Determine the tempe

Serhud [2]

Answer:

281 K

Explanation:

Charles's Law. V1/T1 = V2/T2.

The temperature must be in K = 21.6°C + 273 = 294.6K.

V1T2 = V2T1.

3.62L x T2 = 3.45L x 294.6K

T2 = (3.45 x 294.6) / 3.62 = 1016.4 / 3.62 = B): 281K.

(By direct proportion of volume change: (3.45L / 3.62L) x 294.6K = 281K).

6 0

2 years ago

Who exerts more pressure? a) A girl of 50 kg, wearing heels with an area of 1 cm2. b) An elephant of 4000 kg with foot area of 2

Mrrafil [7]

Answer:

The girl exerts more pressure.

Explanation:

Pressure can be defined as the force exerted normally or perpendicularly per unit area.

i.e P = F/A

Girls

Area of the heel = 1cm² = 10^(-4) m²

Force = mg = 50 × 10 = 500N

Pressure =

$\frac{500}{10 ^{ - 4} }$

$= 5 \times {10}^{6}$

Elephant

Area = 250cm² = 2.5 x 10^(-2)b m²

Force = mg = 40000N

Pressure =

$\frac{40000}{2.5 \times {10}^{ - 2} }$

$= 1.6 \times {10}^{6}$

5 0

3 years ago

Two vectors pointing right starting at the same position. Vector A is on top and longer. Vector B is shorter and below.

Oksana_A [137]

Answer:

The displacements are not equal. While their direction is the same, their length (i.e., distance or magnitude) is not. A is longer than B.

Explanation:

correct on e2020- sample respnse

4 0

3 years ago

Read 2 more answers

Someone pls answer this

andriy [413]

Answer:

The speed of metal block B is 5 m/s after the collision

Explanation:

Law Of Conservation Of Linear Momentum

The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is

P=mv.

If we have a system of bodies, then the total momentum is the sum of them all

$P=m_1v_1+m_2v_2+...+m_nv_n$

If some collision occurs, the velocities change to v' and the final momentum is:

$P'=m_1v'_1+m_2v'_2+...+m_nv'_n$

In a system of two masses, we have:

$m_1v_1+m_2v_2=m_1v'_1+m_2v'_2$

The metal block A has a mass of m1=3.2 Kg and moves at v1=4 m/s. Metal block b has a mass of m2=1.6 Kg and is initially at rest v2=0.

After the collision occurs, block A moves at v1'=1.5 m/s. We need to calculate the speed of the metal block B. Solving for v2':

$\displaystyle v'_2=\frac{m_1v_1+m_2v_2-m_1v'_1}{m_2}$

Substituting the given values:

$\displaystyle v'_2=\frac{3.2*4+1.6*0-3.2*1.5}{1.6}$

$\displaystyle v'_2=\frac{8}{1.6}$

$\displaystyle v'_2=5\ m/s$

The speed of metal block B is 5 m/s after the collision

8 0

2 years ago