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borishaifa [10]
3 years ago
9

The Earth rotates on its axis. what is it's axis.​

Physics
1 answer:
Tomtit [17]3 years ago
3 0

Answer:

The thing where the 2 poles sit

Explanation:

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Vibrations that move through the ground carrying the energy released during an earthquake are called
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A rigid tank initially contains 1.4 kg saturated liquid water at 200◦C. At this state, 25 percent of the volume is occupied by w
rjkz [21]

Answer:

(a) Volume of the tank is 6.47\times 10^{- 3}\ m^{3}

(b) Temperature is 371^{\circ}C

Pressure is 21.3 kPa

(c) The change in internal energy is 1373.54 kJ/kg

Solution:

As per the question:

Mass of liquid in the tank, m = 1.4 kg

Temperature, T = 200^{\circ}C

Volume occupied by water, V = 25%V_{t} = 0.25V_{t}

Volume occupied by air, V' = 75%V_{t}

where

V_{t} = Volume of tank

Now,

(a) In order to calculate the volume of the tank, we make use of the steam table for specific volume at  as given temperature:

At 200^{\circ}C, the specific volume, v = 0.001157m^{3}/kg

At 200^{\circ}C, the internal energy, u = 850.46 kJ/kg

Now,  Volume of water, V = mv = 1.4\times 0.001157 = 1.62\times 10^{- 3} m^{3}

Thus

V = 0.25V_{t}

V_{t} = \frac{1.62\times 10^{- 3}}{0.25} = 6.47\times 10^{- 3}\ m^{3}

(b) For the final temperature and pressure, we calculate the specific volume, v' and then find the corresponding temperature and pressure from the steam table:

v' = \frac{V_{t}}{m} = \frac{6.47\times 10^{- 3}}{1.4} = 4.63\times 10^{- 3}\ m^{3}/kg

The corresponding temperature to this specific volume, T' = 371^{\circ}C

The corresponding pressure to this specific volume, P' = 21.3 kPa

The corresponding internal energy to this specific volume, u' = 2224 kJ/kg

(c) The change in the internal energy of water is given by:

\Delta U = u' - u = 2224 - 850.46 = 1373.54 kJ/kg

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3 years ago
A plane mirror is placed to the right of an object. The image formed by the mirror will be a
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Answer:

A plane mirror is placed to the right of an object. The image formed by the mirror will be a virtual image that appears to be on the left of the mirror.

Explanation:

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3 years ago
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A quantity of 14.1 cm^3 of water at 8.4°C is placed in a freezer compartment and allowed to freeze to solid ice at -7.2°C. How m
serious [3.7K]

Answer:920.31 J

Explanation:

Given

Volume of water (V)=14.1 cm^3

mass(m)=\rho \times V=1000\times 14.1\times 10^{-6}=14.1 gm

Temperature =8.4^{\circ} C

Final Temperature =-7.2 ^{\circ}C

specific heat of water(c)=4.184 J/g-^{\circ}C

Therefore heat required to removed is

Q=mc(\Delta T)

Q=14.1\times 4.184\times (8.4-(-7.2))

Q=920.31 J

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4 years ago
50.0 g of HI is injected into an evacuated 5.00-L rigid cylinder at 340 K. What is the total pressure inside the cylinder when t
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Answer:

P = 2.18 atm

Explanation:

The strategy here here is to use the ideal gas law

PV = nRT

since we know the temperature, volume and the n, the number of moles is mass/MW, and R is the gas constant 0.08205 LatmK⁻¹mol⁻¹:

MW HI = 127.91 gmol⁻¹

P = ( mass / MW ) x R x T / V

P= (50.0 g / 127.91 gmol⁻¹ ) x 0.08205 LatmK⁻¹mol⁻¹  x 340 K/ 5.00 L

P = 2.18 atm

( rounded to three significant figures which is the number of significant figures for temperature, mass and volume )

6 0
4 years ago
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