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Dmitrij [34]
2 years ago
14

Need Answer ASAP only 3 min

Mathematics
2 answers:
ivann1987 [24]2 years ago
6 0

The answer to 29:

D

The answer to 6:

G

mash [69]2 years ago
3 0
Respiratory on the first one
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Need simplified please
Romashka-Z-Leto [24]

Answer:

70

Step-by-step explanation:

7^2 - ( 6-3^3)

PEMDAS

Parentheses first

7^2 - ( 6-3^3)

The exponent in the parentheses first

7^2 - ( 6-27)

7^2 - ( -21)

Now the exponent

49 - (-21)

Now subtract

49 +21

70

6 0
3 years ago
A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from thi
SVETLANKA909090 [29]

Complete question:

Consider a class of 20 students consisting of 5 sophomores, 8 juniors, and 7 seniors. A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from this class, keeping track (in order) of the level of the student that he gets.

1a. How many possible outcomes are in the sample space S? (An outcome is a 5- tuple of students.)

Let A2 denote the event that exactly 2 of the selected students are sophomore, A5 denote the event that exactly 5 of the selected students are the juniors, and A4 denote the event that exactly 4 of the selected students are seniors.

1b. Find the probabilities of each of these three events. A2, A5, A4

1c. Do the events A2, A5, A4 constitute a partition of the sample space?

Answer:

Given:

n = 20

a) The possible outcome in the sample space,S, =

ⁿCₓ = ²⁰C₅

= \frac{20!}{(20-5)! 5!)}

= \frac{20*19*18*17*16}{5*4*3*2*1}

= 15504

b) probabilities of A2, A5, A4

P(A2) = ⁵C₂ / ²⁰C₂

= \frac{20}{320} = \frac{1}{19}

P(A5) = ⁸C₅ / ²⁰C₅

= \frac{56}{15540} = \frac{7}{1938}

P(A4) = ⁷C₄ / ²⁰C₄

= \frac{35}{4845} = \frac{7}{969}

c) No,the events A2, A5, A4, do not comstitute a partition of the sample space. i.e P(A2)+P(A5)+P(A4) ≠ 1

5 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST!
NeX [460]
It has to be B since it shoes both boys and girls.
7 0
2 years ago
Read 2 more answers
6+2x+4(x+5) <br><br><br><br> Please ASAP and you get points b
Zanzabum
Factor is 2(13+3x)
Simplify is 26+6x
6 0
3 years ago
Linear equation
Mazyrski [523]
<h2><u>Answer:</u></h2>

Susan = x

Gina = 3x

Sum of their ages = 12

Susan's age = ?

We can see that,

2x=10x = \frac{10}{2}x= 210  x = 5x=5

Susan is <u>3</u><u> </u><u>years </u>old.

6 0
3 years ago
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