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harkovskaia [24]
3 years ago
13

Please help!! please answer if you know any of them!

Physics
1 answer:
PSYCHO15rus [73]3 years ago
6 0

Answer:

5. 343j

Explanation:

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Based electromagnetic spectrum? on its surface temperature of 6,000 K, most photons that leave the Sun's surface lie in which re
masha68 [24]

Answer:

option C

Explanation:

given,

Temperature of the surface = 6000 K

using formula to calculate \lambda_{max}

\lambda_{max} = \dfrac{0.0029\ K.m}{T}

\lambda_{max} is the maximum wavelength emission in meter.

T is the temperature in kelvin.

\lambda_{max} = \dfrac{0.0029}{6000}

\lambda_{max} = \dfrac{0.0029}{6000}

\lambda_{max} = 4.8333 \times 10^{-7}

\lambda_{max} = 4833\ A^0

the wavelength is in Visible range

The Correct answer is option C

7 0
4 years ago
A flat screen is located 0.55 m away from a single slit. Light with a wavelength of 544 nm (in vacuum) shines through the slit a
kobusy [5.1K]

Answer:

Explanation:

The diffraction pattern is given as

Sinθ = mλ/ω

Where m=1,2,3,4....

Now, when m=1

Sinθ = λ/ω

Then,

ω = λ/Sinθ

The width of the central bright fringe is given as

y=2Ltanθ. From trigonometric

Then,

θ=arctan(y/2L)

Given that,

y=0.052m

L=0.55m

θ=arctan(0.052/2×0.55)

θ=arctan(0.0473)

θ=2.71°

Substituting this into

ω = λ/Sinθ

Since λ=544nm=544×10^-9m

Then,

ω = 544×10^-9/Si.2.71

ω = 1.15×10^-5m.

5 0
3 years ago
A road perpendicular to a highway leads to a farmhouse located 55 mile away. an automobile traveling on the highway passes throu
saveliy_v [14]

The answer in this question is 44.7533 mphGiven information which we denote I as the distance of the automobile between the farmhouse, and S = the distance past the intersection of the highway and the road. 
Then I^2 = 5^2 + s^2. Taking the derivative of both sides of this equation yields 2I(ds/dt) = 2s(ds/dt), so (dl/dt) = s(ds)/I(dt). When the automobile is 7 miles past the intersection we have;dl/dt = 55√(7/5^2 +7^2) and gives us the answer of approximately 44.7533 mph
3 0
4 years ago
Jack is falling down the hill at a speed of 12 m/s. If Jack has a mass of 45 kg, what is his kinetic energy?
Sindrei [870]

Explanation:

KE = ½ mv²

KE = ½ (45 kg) (12 m/s)²

KE = 3240 J

8 0
3 years ago
Any two ways to reduce sound pollution
charle [14.2K]

Answer:

use earplugs

stay away from noisy areas

lower the volume

8 0
3 years ago
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