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mars1129 [50]
4 years ago
6

If two identical bowling balls are raised to the same height, one on Earth and the other on the moon, which has the larger poten

tial energy relative to the surface of the bodies?
Physics
1 answer:
mash [69]4 years ago
5 0

Answer:

"The bowling ball on Earth will have a greater potential energy relative to the surface because the Earth has a much greater mass, and therefore a much stronger gravitational acceleration."

Explanation:

Potential energy acts as a result of the object placed over the Earth's surface, The object has the ability to fall because of the gravitational force. Gravitational potential  energy is based on the weight of the object and also the height above the ground surface. But the elastic potential energy acts due to the shape of the object. Potential energy is related with the restoring of the forces which is the spring or the force of the gravity.

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Suppose that the acceleration of a model rocket is proportional to the difference between 100 ft/sec and the rocket's velocity.
sp2606 [1]

Answer:

Explanation:

initial velocity, u = 0

final velocity, v = 80 ft/s

acceleration, a = 150 ft/s²

Let the time taken is t.

v = u + at

80 = 0 + 150 x t

t = 0.53 second

3 0
3 years ago
Make the following conversion.<br><br> 50.5 cm = _____ hm
Rina8888 [55]
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3 0
3 years ago
Read 2 more answers
Two-out-of-tune flutes play the same note. One produces a tone that has a frequency of 250 Hz, while the other produces 266 Hz.
Andru [333]

Answer:

 x = 259 Hz

Explanation:

given,

frequency of one tuning fork = 250 Hz

frequency of another tuning fork = 266 Hz

when a tuning fork is sounded together beat frequency heard = 9

 let x be the frequency of unknown

 x - 250 = 9 Hz..............(1)

 x = 259 Hz

when a another tuning fork is sounded together beat frequency heard = 7

266 - x  = 7 Hz..............(2)

 x = 259 Hz

now, on solving both the equation the frequency comes out to be 259 Hz.

so, The frequency of the tuning fork is equal to 259 Hz

6 0
4 years ago
A projectile is launched with an initial velocity of (40 m/s), at an angle of (30°) above
zlopas [31]

Answer:

330.5  m

Explanation:

In this case, the object is launched horizontally at 30° with an initial velocity of 40 m/s .

The maximum height will be calculated as;

h=\frac{v^2_isin^2\alpha }{2g}

where ∝ is the angle of launch = 30°

vi= initial launch velocity = 40 m/s

g= 10 m/s²

h= 40²*sin²40° / 2*10

h={1600*0.4132 }/ 20

h= 661.1/2 = 330.5  m

8 0
3 years ago
Lila swam 50 meters north in 10 seconds. Find Lila's velocity
In-s [12.5K]

Explanation:

50 meters north in 10 seconds.

speed = distance ÷ time = 50 meters ÷ 10 seconds = 5m/s

8 0
3 years ago
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