Answer:
Explanation:
initial velocity, u = 0
final velocity, v = 80 ft/s
acceleration, a = 150 ft/s²
Let the time taken is t.
v = u + at
80 = 0 + 150 x t
t = 0.53 second
50.5cm= 0.00505hm
Hope this helps!
Answer:
x = 259 Hz
Explanation:
given,
frequency of one tuning fork = 250 Hz
frequency of another tuning fork = 266 Hz
when a tuning fork is sounded together beat frequency heard = 9
let x be the frequency of unknown
x - 250 = 9 Hz..............(1)
x = 259 Hz
when a another tuning fork is sounded together beat frequency heard = 7
266 - x = 7 Hz..............(2)
x = 259 Hz
now, on solving both the equation the frequency comes out to be 259 Hz.
so, The frequency of the tuning fork is equal to 259 Hz
Answer:
330.5 m
Explanation:
In this case, the object is launched horizontally at 30° with an initial velocity of 40 m/s .
The maximum height will be calculated as;

where ∝ is the angle of launch = 30°
vi= initial launch velocity = 40 m/s
g= 10 m/s²
h= 40²*sin²40° / 2*10
h={1600*0.4132 }/ 20
h= 661.1/2 = 330.5 m
Explanation:
50 meters north in 10 seconds.
speed = distance ÷ time = 50 meters ÷ 10 seconds = 5m/s