Answer:
All the competitors will move with the same velocity.
Explanation:
Here, the situations for each competitor are identical. Thus, they will exert the same force and hence, their velocities at each instants will be identical.
Answer:
Friction 100 j
Explanation:
Friction causes the inequality between PE and KE
100 J
A motorboat accelerates uniformly from a velocity of 6.5m/s
to the west to a velocity of 1.5m/s to the west. if its accelerate was 2.7m/s2
to the east ,
how far did it travel during the accelration? Give your
answer in units of kilometers per hour/sec. To find the acceleration of the car
we have to
<span>
1. First determine
the suitable formula for this word problem.
Which is a. A=vf-vi/t</span>
which will be
Given are: Vi= 6.5 m/s Vf= 1.5 m/s a= 2.7 m/sec2 t=1.85s
Solution:
<span>
x = v0t + ½at2</span>
<span>x = <span>16.645375 m </span></span>
Answer : The correct option is, (C) 17 m/s
Explanation :
Formula used :
![K.E=\frac{1}{2}mv^2](https://tex.z-dn.net/?f=K.E%3D%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
where,
K.E = kinetic energy = 6.8 J
m = mass of object = 46 g = 0.046 kg (1 kg = 1000 g)
v = velocity
Now put all the given values in the above formula, we get:
![K.E=\frac{1}{2}mv^2](https://tex.z-dn.net/?f=K.E%3D%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
![6.8J=\frac{1}{2}\times 0.046kg\times v^2](https://tex.z-dn.net/?f=6.8J%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%200.046kg%5Ctimes%20v%5E2)
![6.8kg.m^2/s^2=\frac{1}{2}\times 0.046kg\times v^2](https://tex.z-dn.net/?f=6.8kg.m%5E2%2Fs%5E2%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%200.046kg%5Ctimes%20v%5E2)
![v=17.19m/s\approx 17m/s](https://tex.z-dn.net/?f=v%3D17.19m%2Fs%5Capprox%2017m%2Fs)
Therefore, the ball's velocity be as it leaves the cannon is, 17 m/s
The initial is where you are starting and the final postion is where the object ends up