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BigorU [14]
2 years ago
10

What is the slope of the line that passes through the points (10, 3) and (2, 3) ?

Mathematics
2 answers:
irinina [24]2 years ago
7 0
<h3>Answer:  slope = 0</h3>

Work Shown:

Use the slope formula

m = (y2 - y1)/(x2 - x1)

m = (3-3)/(2-10)

m = 0/(-8)

m = 0

The slope of any horizontal line is always zero due to the fact all y coordinates on this line are the same. When we pick two points from the line, the same y coordinates subtract to 0. We can have 0 in the numerator, but not in the denominator.

As the slope formula shows, we basically subtract the y coordinates together, and do the same for the x coordinates as well in the same order. Then we divide the differences.

Margarita [4]2 years ago
3 0
Slope: (y2-y1)/(x2-x1)
(3-3)/(2-10) = 0/-8 = 0
The slope is 0
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Consider the statements below. Which are not propositions? Mark all that apply.
Troyanec [42]

Answer:

In Idaho, there are 15 temples for the Church of Jesus Christ of Latter-day Saints.

A delicious chocolate cake.

The great and spacious building.

3+5=8

5+3=53

Step-by-step explanation:

To determine which statement is a propositions or not first, we need to define the concept of preposition:

<em>A statement that can be either true or false.</em>

That means it should declare unequivocal information about something.

A question is not declaring something to be true or false. Therefore, it is not a proposition.

The recommendation of "should get" is not a direct statement.

No way! is not referring to anything to be either true or false.

7 0
2 years ago
20 pts need this question asap
AlekseyPX
It's D because 140÷3.50 is 40
7 0
3 years ago
-4a &lt;-32 what is the answer
Fiesta28 [93]

Answer:

a > 8

Step-by-step explanation:

Divide by the coefficient of the variable. Since it is negative, the direction of the comparison must be reversed.

(-4a)/(-4) > (-32)/(-4)

a > 8

6 0
2 years ago
Brittany will be working full time this summer to save for her goal of having 10,000 by the time she is 21. Brittany has an acco
photoshop1234 [79]

Answer:

$ 8,695.35

Step-by-step explanation:

This is a compound interest question

Amount after t years = A = P(1 + r/n)^nt

Where P = Initial Amount saved

r = interest rate

t = time in years

n = compounding frequency

A = 10,000

r = 3.5 %

t = 21 - 17 = 4 years

n = Compounded monthly = 12

Step 1

Converting R percent to r a decimal

r = R/100 = 3.5%/100 = 0.035 per year.

P = A / (1 + r/n)^nt

Solving our equation:

P = 10000 / ( 1 + (0.035/12)^12 ×4 =

P = $8,695.35

The principal investment required to get a total amount, principal plus interest, of $10,000.00 from interest compounded monthly at a rate of 3.5% per year for 4 years is $8,695.35.

8 0
2 years ago
How many pounds of a 15% copper alloy must be mixed with 700lb of a 30% copper alloy to maybe a 25.5% copper alloy
lisov135 [29]

Answer:

300\; \rm lb.

Step-by-step explanation:

Let x represent the mass (in pounds) of that 15\% copper alloy required, such that the final mixture would contain 25.5\% copper by mass.

Consider: if x pounds of that 15\% copper alloy is mixed with 700 pounds that 30\% copper alloy, what would be the mass of copper in the mixture?

  • Mass of copper in x pounds of that 15\% copper alloy: (0.15\, x)\; \rm lb.
  • Mass of copper in 700 pounds of that 30\% copper alloy: 700 \times 0.30 = 210\; \rm lb.

Therefore, the mixture would contain (210 + 0.15\, x) \; \rm lb of copper.

The mass of that mixture would be (700 + x)\; \rm lb. The mass fraction of copper in that mixture would be:

\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\%.

This ratio is supposed to be equal to 25.5\%. These two pieces of equations combine to give an equation about x:

\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\% = 25.5\%.

\displaystyle \frac{210 + 0.15\, x}{700 + x} = 0.255.

Simplify and solve for x:

210 + 0.15\, x= 0.255\, (700 + x).

(0.255 - 0.15)\, x= 210 - 0.255 \times 700.

\displaystyle x = \frac{210 - 0.255 \times 700}{0.255 - 0.15} = 300.

Therefore, 300\; \rm lb of that 15\% alloy would be required.

4 0
2 years ago
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