Can some one help me with 1,2, and 4

Mathematics

2 answers:

Alina [70]2 years ago

4 0

Answer:

I got 76 for #1 your welcome

Likurg_2 [28]2 years ago

4 0

I got 12 for number #2(good luck)

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Rewrite the following equation in standard form and determine if there is a solution.

Debora [2.8K]

Answer:

| x + 4 | = -1 No solution

Step-by-step explanation:

3 | x + 4 | + 12 = 9

Subtract 12 from both sides: 3 | x + 4 | = -3

Divide both sides by 3: | x + 4 | = -1

Absolute value cannot be negative, so there is no solution.

5 0

2 years ago

Factor the polynomial 3x4 – 2x2 + 15x2 - 10 by grouping.

prohojiy [21]

Answer:

see explanation

Step-by-step explanation:

Given

3 $x^{4}$ - 2x² + 15x² - 10

Factor the first/second and third/fourth terms )

= x²(3x² - 2) + 5(3x² - 2) ← factor out (3x² - 2) from each term

= (3x² - 2)(x² + 5)

4 0

2 years ago

Read 2 more answers

Perform the indicated operation:

yaroslaw [1]

The expression $\frac{m^{2}-16\cdot n^{2}}{\frac{3\cdot m + 12\cdot n}{m\cdot n} }$ is equal to $\frac{m^{2}\cdot n}{3} -\frac{4\cdot m\cdot n^{2}}{3}$ .

<h3>How to simplify a composite algebraic expression</h3>

In this question we must use properties of <em>real</em> algebra to simplify a given expression as most as possible. We proceed to show each step with respective reason.

$\frac{m^{2}-16\cdot n^{2}}{\frac{3\cdot m + 12\cdot n}{m\cdot n} }$ Given
$\frac{m\cdot n \cdot (m^{2}-16\cdot n^{2})}{3\cdot m + 12\cdot n}$ $\frac{\frac{a}{b} }{\frac{c}{d} } = \frac{a\cdot d}{c\cdot b}$
$\frac{m\cdot n \cdot (m-4\cdot n)\cdot (m+4\cdot n)}{3\cdot (m+4\cdot n)}$ Distributive property/ $a^{2}-b^{2} = (a +b)\cdot (a-b)$
$\frac{m\cdot n \cdot (m-4\cdot n)}{3}$ Existence of the multiplicative inverse/Modulative property
$\frac{m^{2}\cdot n}{3} -\frac{4\cdot m\cdot n^{2}}{3}$ Distributive property/ $x^a\cdot x^{b} = x^{a+b}$ /Result