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4vir4ik [10]
3 years ago
9

Why is carbon IV oxide and water removed before liquefication of air?​

Chemistry
1 answer:
jeka57 [31]3 years ago
6 0

Answer:

Because when they unfreeze and are cooled they would block pipes of the air liquefaction plant and make the air colder, hope this helps!!

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What is 4,678,679 dL in scientific notation
vesna_86 [32]
4.7e^6 is how I would write it. You simply count in from the right side where the decimal is until you reach the point just before the 4.
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3 years ago
How many grams are in 0.220 mol of Ne?
kumpel [21]

Answer:

4.44 g Ne

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

0.220 mol Ne

<u>Step 2: Identify Conversions</u>

Molar Mass of Ne - 20.18 g/mol

<u>Step 3: Convert</u>

<u />0.220 \ mol \ Ne(\frac{20.18 \ g \ Ne}{1 \ mol \ Ne} ) = 4.4396 g Ne

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

4.4396 g Ne ≈ 4.44 g Ne

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3 years ago
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Please fill in the blank: structures are fully functional, show evidence of a common ancestor, and may or may not have the same
Vinil7 [7]

Answer:

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Hope It Helps!

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True or False Chromium- 63 has 39 neutrons
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Answer:

false

Explanation:

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3 years ago
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g 32.53 g of a solid is heated to 100.oC and added to 50.0 g of water in a coffee cup calorimeter and the contents are allowed t
Radda [10]

Answer:

0.886 J/g.°C

Explanation:

Step 1: Calculate the heat absorbed by the water

We will use the following expression

Q = c × m × ΔT

where,

  • Q: heat
  • c: specific heat capacity
  • m: mass
  • ΔT: change in the temperature

Q(water) = c(water) × m(water) × ΔT(water)

Q(water) = 4.184 J/g.°C × 50.0 g × (34.4 °C - 25.36 °C) = 1.89 × 10³ J

According to the law of conservation of energy, the sum of the energy lost by the solid and the energy absorbed by the water is zero.

Q(water) + Q(solid) = 0

Q(solid) = -Q(water) =  -1.89 × 10³ J

Step 2: Calculate the specific heat capacity of the solid

We will use the following expression.

Q(solid) = c(solid) × m(solid) × ΔT(solid)

c(solid) = Q(solid) / m(solid) × ΔT(solid)

c(solid) = (-1.89 × 10³ J) / 32.53 g × (34.4 °C - 100. °C) = 0.886 J/g.°C

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