1 = 90
2 = 65
3 = 65
4 = 25
90+25=115
180-115=65
have a merry christmas :)
The equation which models the distance (d) of the weight from its equilibrium after time (t) is equal to d = -9cos(2π/3)t.
<h3>What is the period of a cosine function?</h3>
The period of a cosine function simply means the total length (distance) of the interval of values on the x-axis over which a graph lies and it's repeated.
Since the weight attached is at its lowest point at time (t = 0), therefore, the amplitude of equation will be negative nine (-9)
For the angular velocity at time period (t = 3s), we have:
ω = 2π/T
ω = 2π/3
Mathematically, the standard equation of a cosine function is given by:
y = Acos(ω)t
Substituting the given parameters into the formula, we have;
d = -9cos(2π/3)t.
Read more on cosine function here: brainly.com/question/4599903
Answer:
See explanation below.
Step-by-step explanation:
First I'm going to find angle 2. Angle two plus 55 is equal to 115. 180-115=65. 65-55=10 Angle 2 = 10
Next, we can find angle 3. 55+10=65. 180-65=115. Angle 3 = 115
Angle 2 is equal to angle 5, angle 3 is equal to angle 6, and angle 4 is equal to 55.
Angle 5 = 10
Angle 4 = 55
Angle 6 = 115
Now we can find angle 8. 180-115=65. Angle 8 = 65
Angle 11 = 65
Angle 12 = 115
10+115=125 Angle 10 = 125
180-125 = 55 Angle 9 = 55
Angle 14 = 55
Angle 13 = 125
Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.
Step-by-step explanation:
Total number of students = 8
Number of student who has passed Exam P/1 = 1
Number of student who has passed Exam FM/2 = 1
No student has passed more than one exam.
According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.
So, Probability will be
Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.
