Y = 2x + 1
y = x²+1
reemplazando
2x+1 = x²+1
ordenando
0=x²-2x
donde
0 = x (x-2)
resolviendo
0=x v x-2=0
0 =x x= 2
si x=0 entonces y = 1 par (0,1)
si x=2 entonces y= 5 par (2,5)
respuesta A
answer: Rolling Two Dice. Note that there are 36 possibilities for (a,b). This total number of possibilities can be obtained from the multiplication principle: there are 6 possibilities for a, and for each outcome for a, there are 6 possibilities for b. So, the total number of joint outcomes (a,b) is 6 times 6 which is 36.
Step-by-step explanation: hopefully this is right
Answer:
Hope this helps
Step-by-step explanation:
4. 10^2
5. 64 / 14 * 9 + 8
64/126+8
8 64/126
8 4/9
6. 1.762 x 10^3
Lol battlefield or on a map when you're look for a particular place
Answer:
x=3,y=0
x=-1,y=0
Step-by-step explanation:
We will have to factorise to get the value of x before solving for y
Let's solve
y=x^2-2x-3
To factorise x
x^2-3x+x-3
x(x-3)+1(x-3)
(x-3)+(x+1)
x-3=0
x=3
x+1=0
x=-1
Let's substitute the value of value to get the value for y
y=x^2-2x-3
When x is 3
y=3^2-2(3)-3
y=9-6-3
y=0
When x is-1
y=(-1)^2-2(-1)-3
y=1+2-3
y=0
Therefore when x is 3,y is 0
When x is -1,y is 0