Answer:
24.57 revolutions
Explanation:
(a) If they do not slip on the pavement, then the angular acceleration is
(b) We can use the following equation of motion to find out the angle traveled by the wheel before coming to rest:
where v = 0 m/s is the final angular velocity of the wheel when it stops, 
= 95rad/s is the initial angular velocity of the wheel, 
is the deceleration of the wheel, and 
is the angle swept in rad, which we care looking for:
As each revolution equals to 2π, the total revolution it makes before stop is
154.375 / 2π = 24.57 revolutions
Answer:
The work done to get you safely away from the test is 2.47 X 10⁴ J.
Explanation:
Given;
length of the rope, L = 70 ft
mass per unit length of the rope, μ = 2 lb/ft
your mass, W = 120 lbs
mass of the 70 ft rope = 2 lb/ft x 70 ft
= 140 lbs.
Total mass to be pulled to the helicopter, M = 120 lbs + 140 lbs
= 260 lbs
The work done is calculated from work-energy theorem as follows;
W = Mgh
where;
g is acceleration due gravity = 32.17 ft/s²
h is height the total mass is raised = length of the rope = 70 ft
W = 260 Lb x 32.17 ft/s² x 70 ft
W = 585494 lb.ft²/s²
1 lb.ft²/s² = 0.0421 J
W = 585494 lb.ft²/s² = 2.47 X 10⁴ J.
Therefore, the work done to get you safely away from the test is 2.47 X 10⁴ J.
Answer:
Current that reverses direction in the regular pattern is called an alternating current, abbreviated as 'AC'.
Explanation:
hope this helps!
Is there a question? Because All your doing t explaining a british philosopher to us..
Answer:
a. 3 s.
Explanation:
Given;
angular acceleration of the wheel, α = 4 rad/s²
time of wheel rotation, t = 4 s
angle of rotation, θ = 80 radians
Apply the kinematic equation below,
Given initial angular velocity, ω₀ = 0
Apply the kinematic equation below;
Therefore, the wheel had been in motion for 3 seconds.
a. 3 s.
