The formula is:
Work = Force · Displacement
F = m · g
F = 16 kg · 9.8 m/s² = 156.8 N
and we know that:
d = 0.8 m
W = 156.8 N · 0.8 m = 125.44 J
Answer:
W = 125.44 J.
Answer:
The final velocity of the car A is -1.053 m/s.
Explanation:
For an elastic collision both the kinetic energy and the momentum of the system are conserved.
Let us call
= mass of car A;
= the initial velocity of car A;
= the final velocity of car A;
and
= mass of car B;
= the initial velocity of car B;
= the final velocity of car B.
Then, the law of conservation of momentum demands that

And the conservation of kinetic energy says that

These two equations are solved for final velocities
and
to give


by putting in the numerical values of the variables we get


and


Thus, the final velocity of the car A is -1.053 m/s and of car B is 3.49 m/s.
Answer:
P₀ = 5.76 x 10⁻² MW
Explanation:
given,
efficiency of the power plant = 32%
Power produced by the nuclear fission = 0.18 MW
the power plant output = ?
using formula of efficiency

where P is the power produced in the power plant
P₀ is the power output of the power plant


P₀ = 0.18 x 0.32
P₀ = 0.0576 MW
P₀ = 5.76 x 10⁻² MW
Power plant output is equal to P₀ = 5.76 x 10⁻² MW