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Anton [14]
2 years ago
15

Which of the following would not be found in the kingdoms Protista, Fungi, Plantae, or Animalia?

Biology
2 answers:
Orlov [11]2 years ago
8 0
B. prokaryotes because they do not contain organelles or a nucleus. the following above in the question all are eukaryotic and contain organelles and a nucleus
____ [38]2 years ago
4 0

Answer:

B

Explanation:

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Anybody wanna join my quiziz :DD
Musya8 [376]
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Answer the following:
mihalych1998 [28]
A. behavioral isolation is when the plant or animal acts a particular way to attract their counterparts, like mating rituals.

geographic isolation is the natural barrier preventing similar species from interacting. for example, Galapagos Islands are the only home of flightless cormorants because the islands are so far from any other land for them to invade.

Temporal isolation is when two of the same or similar species cannot reproduce as a result of mismatched sexual maturity.

B. the isolation of two frog species by mating call is behavioral isolation.
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3 years ago
If a heterozygous plant with green seeds self-fertilizes, what is the probability that 6 seeds in a single pod of the progeny pl
nalin [4]

Here is the complete question

The seeds in bush bean pods are each the product of an independent fertilization event. Green seed color is dominant to white seed color in bush beans.

If a heterozygous plant with green seeds self-fertilizes, what is the probability that 6 seeds in a single pod of the progeny plant will consist of:

A) 4 green and 2 white seeds?

B) all white seeds?

C) at least 5 white seeds?

Answer:

A) 0.3

B) 0.0002

C) 0.001

Explanation:

Let the allele for Green plant be = P

Let the allele for white plant be =  p

Let the heterozygous plant be Pp, if self fertilization occurs we have:

                   P                    p

P                 PP                 Pp                                                              

                                                           

p                 Pp                 pp                  

From the punnet square above, we have the following  cross;

PP, Pp, Pp, pp

Since P is dominant to p; we have a phenotypic ratio of 3:1 between the dominant phenotype ( PP, Pp, Pp ) and recessive phenotype ( pp )

NOW, the probability for the green plant(i.e PP or Pp) will be: Pr(G)=\frac{3}{4}

the probability for the white plant (pp) will be: Pr (W)= \frac{1}{4}

A)

what is the probability that 6 seeds in a single pod of the progeny plant will consist of 4 green and 2 white seeds?

Pr(4G2W) = (\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{1}{4})*(\frac{1}{4})

The probability includes the use of permutation:

Permutation(P)=\frac{6!}{(4!*2!)} * (\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{1}{4})*(\frac{1}{4})

= 15*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{1}{4})*(\frac{1}{4})

= 0.2966

≅ 0.3

B)

What is the probability that 6 seeds in a single pod of the progeny plant will consist of all white seeds?

Since probability for white seed = \frac{1}{4}

The probability that 6 seeds will consist of all white seeds will be = (\frac{1}{4})^6

=  2.44 × 10⁻⁴

= 0.000244

≅ 0.0002

C)

What is the probability that 6 seeds in a single pod of the progeny plant will consist of at least 5 white seeds?

For at least 5 white seeds, the probability will consist of  5 white seeds and 6 white seeds.

For 5 white seeds; we have:

5 White  and 1 Green  Since there are 6 permutations.

The probability For 5 white seeds will therefore be :

Pr(5 seeds)=(\frac{1}{4})^5*(\frac{3}{4})^1 *6

= 7.32 × 10⁻⁴

= 0.000732

For 6 white seeds; we have:

Only one permutation for 6 whites since there will no be any presence of any green seed.

Pr(6seeds)=(\frac{1}{4})^6

= 2.44 × 10⁻⁴

= 0.000244

∴

The total probability for at least 5 white seeds =  0.000732 + 0.000244

= 9.76  × 10⁻⁴

= 0.000976

≅ 0.001

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