Proteins
Proteins are used for cellular repairing and chemical processes. Ribosomes are one of the most important organelles in the cell, mostly part of the rough endoplasmic reticulum. It manufactures enzymes such as proteins which will be utilized by many organelles in the cell. Microtubules are one, responsible for the framework and acts as a skeleton of the cell –cytoskeleton needs proteins, also cytoplasm and other organelles of the cell. For a prokaryote or a eukaryote cell to survive, they need protein.<span> Fundamentally, the cell would cease to function and possibly die</span>
Answer:
1600km * 2 / 1000 = 3.2cm
2400km* 2/ 1000 = 4.8cm
2880km * 2/ 1000 =5.76cm
Explanation:
Answer:
Explanation:
<em>Let the ability to break down the red color in beets be represented by the allele </em><em>B</em><em>. The inability would be represented by the allele </em><em>b</em><em>.</em>
A nonsecretor's genotype would be BB or Bb while a secretor's genotype would be bb.
A nonsecretor woman with a secretor father would be a carrier with genotype Bb. A nonsecretor man who in a previous marriage had a secretor daughter would also be a carrier with genotype Bb. If the two marries:
<em>Bb x Bb</em>
<em> BB 2Bb bb</em>
1.
(a) probability of their first child will be a secretor girl = probability of having a girl and being a secretor.
Probability of having a girl = 1/2
Probability of being a secretor = 1/4
<em>probability of their first child will be a secretor girl</em> = 1/2 x 1/4 = 1/8
(b) Probability of their first child being a nonsecretor girl = probability of having a girl and being a nonsecretor.
Probability of having a girl = 1/2
Probability of being a nonsecretor = 3/4
<em>Probability of their first child being a nonsecretor girl = probability of having a girl and being a nonsecretor</em> = 1/2 x 3/4 = 3/8
2. <em>Probability that their first two children will be nonsecretors of either sex = probability of their first being a nonsecretor and of either sex and probability of their second being a nonsecretor and of either sex.</em>
= 3/4 x 3/4 = 9/16
The bicarbonate buffering system in the blood is the most important buffering system in the ECF. Bicarbonate ion and carbonic acid are the key components of this buffering system. The weak base <u>bicarbonate</u> serves to buffer the strong acid <u>H+</u><u>.</u> The buffer to the strong base <u>OH-</u><u> </u>is <u>carbonic acid</u>. The byproduct of these reactions is <u>water.</u>
Explanation:
A buffer system utilizes chemical buffers and resists any changes in the pH and adjusts acidity and alkalinity of the medium by binding or releasing H+ ions accordingly.
A bicarbonate buffering system in the ECF regulates the bicarbonate level and maintains the normal acidity level of blood.
Sodium bicarbonate reacting with a strong acid (HCl) produces a weak acid (carbonic acid) and sodium chloride. A strong base like (NaOH) reacts with carbonic acid producing bicarbonate and water.
NaHCo3 + HCl → H2CO3 + NaCl
H2Co3 + NaOH → HCO3 + H20
The acidity of the blood is regulated by maintaining the ratio of bicarbonate and carbonic acid at 20:1 under normal conditions through the bicarbonate buffer system. The carbonic acid level is regulated by the respiratory system; while carbonate level is regulated by the renal system.
