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3 years ago

What is the algebraic expression for "two times the sum of a number n and 24"?

Mathematics

1 answer:

konstantin123 [22]3 years ago

3 0

Answer:

B. 2(n + 24)

Step-by-step explanation

you need to find the sum of n and 24 first so you put it in brackets. To multiply by two just put 2 on the outisde of the brackets.

Hope this helps

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A television and DVD player cost a total of 1132. The cost of the television is three times the cost of the DVD player. What is

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Let x rep cost of dvd in $
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and x + 3x = 1132
4x=1132
x=1132/4
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What is true about △ABC? Select three options

rjkz [21]

Answer:

A) AB ⊥ AC

B) The triangle is a right triangle.

C) The triangle is an isosceles triangle

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

we have

$A(-1,3), B(-5,-1)$

substitute in the formula

$d=\sqrt{(-1-3)^{2}+(-5+1)^{2}}$

$d=\sqrt{(-4)^{2}+(-4)^{2}}$

$d_A_B=\sqrt{32}\ units$

step 2

Find the distance BC

we have

$B(-5,-1),C(3,-1)$

substitute in the formula

$d=\sqrt{(-1+1)^{2}+(3+5)^{2}}$

$d=\sqrt{(0)^{2}+(8)^{2}}$

$d_B_C=8\ units$

step 3

Find the distance AC

we have

$A(-1,3),C(3,-1)$

substitute in the formula

$d=\sqrt{(-1-3)^{2}+(3+1)^{2}}$

$d=\sqrt{(-4)^{2}+(4)^{2}}$

$d_A_C=\sqrt{32}\ units$

step 4

Compare the length sides of triangle

$d_A_B=\sqrt{32}\ units$

$d_B_C=8\ units$

$d_A_C=\sqrt{32}\ units$

therefore

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The triangle ABC is a right triangle because satisfy the Pythagoras theorem

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$64=32+32$

$64=64$ ----> is true (Is a right triangle)

AB ⊥ AC because in a right triangle the legs are perpendicular

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