In order to find the percentage of the litters that will consist of two wavy- haired and three straight-haired offspring, you need to use the binomial distribution formula: P(x) = ⁿCₓ × pₓ × qⁿ⁻ˣ
P is the probability that the litters will consist of two wavy-haired and three straight-haired offspring.
X is considered to be the number of times the offspring will have wavy-air in a litter of 5 offspring, which is 2.
n is the number of offspring per litter.
p is the probability of happening wavy hair.
q is the probability of having straight hair.
It comes like this:
P(X=2)=⁵C₂×0.5²×0.5⁵⁻² ⇔ P(X=2)=10×0.25×0.125 ⇔ P(X=2)=0.3125
So, the percentage of the litters that will consist of two wavy-haired and three straight-haired offspring is 31.25%.
B.) Decreases (As the growth rate of a population increases, the doubling time decreases.)
I just took the test. Edgen says the answer is c. suffocation.
Answer: artery
Explanation:
The artery is the blood vessel that carry oxygenated (oxygen-rich) blood away from the heart while the vein carry deoxygenated(oxygen-poor) blood from the body to the heart.
Hence, all arteries carry oxygenated blood except pulmonary artery while all veins carry deoxygenated blood except pulmonary vein.
Testosterone and serotonin are the two hormones consistently related to high levels of aggression.
