Yes because the protons are the same but the neutrons change
For #4 is 298.48 hope it is correct
Answer: 1123000 Joules of energy are required to vaporize 13.1 kg of lead at its normal boiling point
Explanation:
Latent heat of vaporization is the amount of heat required to convert 1 mole of liquid to gas at atmospheric pressure.
Amount of heat required to vaporize 1 mole of lead = 177.7 kJ
Molar mass of lead = 207.2 g
Mass of lead given = 1.31 kg = 1310 g (1kg=1000g)
Heat required to vaporize 207.2 of lead = 177.7 kJ
Thus Heat required to vaporize 1310 g of lead =
Thus 1123000 Joules of energy are required to vaporize 13.1 kg of lead at its normal boiling point
The substance should be in liquid state.
First, it takes up space in the container, which leads to that it shouldn't be a solid, because solid doesn't change its shape easily.
Second, it has a fixed volume, it's difficult to compress the substance, therefore it shouldn't be gas too, as gas can be compressed easily.
Therefore we're left with liquid. And both of these given properties fits the property of liquid.