So if we use the equation:
→ 
We can then determine the amount of 
needed to produce 208 kg of methanol.
So let's find out how many moles of methanol 208 kg is:
Methanol molar weight = 32.041g/mol
So then we can solve for moles of methanol:
So now that we have the amount of moles produced, we can use the molar ratio (from the balanced equation) of hydrogen and methanol. This ratio is 2:1 hydrogen:methanol.
Therefore, we can set up a proportion to solve for the moles of hydrogen needed:
So now that we have the number of moles of 
that are produced, we can then use the molar weight of hydrogen to solve for the mass that is needed:
Therefore, the amount of diatomic hydrogen () that is needed to produce 208kg of methanol is 
g.
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The atoms C,H,O and N becomes more electronegative as the periodic table's right side and top get increasingly electronegative as you move down it. A hydrogen bond needs to share elements with hydrogen in order to exist.
As you move up and to the right of the periodic table, the electronegative properties increase. To form a hydrogen bond, elements would have to be shared with hydrogen. Each element becomes increasingly electronegative as you move further right on the periodic table, with the exception of noble gases (which aren't particularly reactive).
In order to obtain stability, atoms C, H, O, and N would therefore most likely desire to share their electrons (i.e., they are more electronegative because they wish to "hog" electrons). Due to its intermediate electronegativity, hydrogen has a mid-range potential for forming bonds with other molecules.
Learn more about hydrogen element here:
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