1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alex787 [66]
3 years ago
5

State if the two triangles are congruent. If they are, state how you know.

Mathematics
1 answer:
ankoles [38]3 years ago
6 0

Answer:

Step-by-step explanation:

yes congruent, by AAS

the angles are stating , w/ the little red lines that they are the same.. so we know two angles of the triangles are the same, and we also know that one side touching is the same.   so yes.. AAS.  

You might be interested in
100 POINTS HELP ASAP Linear Combination
notka56 [123]

Answer:

1)   x=\dfrac12

2)   n = -3 \ \ \textsf{and} \ \ m = -4

3)  see below

4)  A:  0 = 1

Step-by-step explanation:

<u>Question 1</u>

15-0.5(4x-2)+4x=17

\implies 15-2x+1+4x=17

\implies 2x+16=17

\implies 2x=1

\implies x=\dfrac12

<u>Question 2</u>

\textsf{rearrange} \ n=m+1 :

\implies -m=-n+1

\textsf{add equations} \ -m=-n+1 \ \textsf{and} \ m=2n+2:\\

\implies0=n+3

\implies n=-3

\textsf{substitute} \ \ n=-3 \ \ \textsf{into} \ \ m=n-1:

\implies m=-3-1

\implies m=-4

<u>Question 3</u>

subtract the second equation from the first

divide both sides by -4

substitute found value for y into first equation

solve for x

<u>Question 4</u>

3j=k

k=3j+1

\textsf{rearrange} \ 3j=k :

\implies -k=-3j

\textsf{add equations}\  -k=-3j \ \ \textsf{and}\ \ k=3j+1:

\implies 0=1

Solution = A

6 0
3 years ago
Joan ran 200 yards in 40 seconds, Bill ran 800 yards in 140 seconds. Who ran at a faster rate? Justify your answer.
Nata [24]
Joan ran 200 yards  divided by 40 seconds=5 seconds per yard
Bill ran 800 yards divided by 140 seconds = 5.714 seconds per yard
So Bill is at 5.7 seconds and Joan at only 5.
Joan I mean. Joan ran faster..........
6 0
3 years ago
Select the statement that best describes the pattern.
Lubov Fominskaja [6]

Answer:

thats Hard.

Step-by-step explanation:

3 0
3 years ago
In a fund-raising game for your school, you bet $1 to roll two dice. If your total is 8,9,10 or 11 you win $2. If your total is
ololo11 [35]

Answer: E , You will lose 5.6 cents

Step-by-step explanation:

Because with two dice, there are 36 possible outcomes, 21 are 7 or less, 14 are 8 through 11, and 1 is twelve.

Also when you have a total of 8,9,10 or 11, you gain $1 deducing the $1 you bet. The same with when you have 12 you gain $5.

Average $ to gain when total is 8,9,10 or 11 = P(8,9,10,11)

P(8,9,10,11) = ($2-$1)(14/36) = $14/36 gain

P(12) = ($6-$1)(1/36) = $5/36 gain

P(7 or less) = (0-$1)(21/36) = -$21/36 loss

P(loss or gain)= P(8,9,10,11) + P(12) + P(7 or less)

P(loss or gain) = $( 14/36 + 5/36 - 21/36) = -$2/36

P(loss or gain) = -$0.056 = -5.6 cents loss

Therefore, For every $1 bet you will lose 5.6 cents.

8 0
3 years ago
Help????? ummmmmmmmmmmmmmmmmm
Effectus [21]
9x9 +10 ok yeeeeeeeeeeeeeeeeey
4 0
3 years ago
Other questions:
  • What needs to be corrected in the following construction for copying ABC with point D as the vertex?
    11·1 answer
  • Simplify (1-√3)(⅓+√3) leaving your answer in the form p+q√3​
    9·1 answer
  • Please help! Need an equation using C and S and points to graph.
    12·2 answers
  • Can someone help me with this
    13·1 answer
  • A recipe for chocolate chip cookies used 3 cups flour and sticks 2 sticks of butter is the amount of butter used proportional to
    15·1 answer
  • Please select the word from the list that best fits the definition
    13·2 answers
  • Hey! please help i’ll give brainliest! if it lets me:)
    5·1 answer
  • How tall is the tree
    9·1 answer
  • I cant figure this one out at all
    9·1 answer
  • Eva measures the mass of 25 children. She calculates the mean and the median of the masses. Eva makes a mistake when measuring t
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!