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Delvig [45]
3 years ago
13

Find the vertex of f(x)=4x^2+8x-2

Mathematics
1 answer:
andrew-mc [135]3 years ago
4 0

Answer:

f(x) =4x^2 + 8x -2 \\f(x) = 4(x^2 + 2x -\frac{1}{2} )\\\\f(x) = 4(x^2 + 2x +1 - 1 -\frac{1}{2} )\\f(x) = 4((x+1)^2 - 1 -\frac{1}{2} ))\\f(x) = 4((x+1)^2 -\frac{3}{2} ))\\f(x) = 4(x+1)^2 -6\\

the vertices (-1, -6)

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