Answer:
Step-by-step explanation:
The amplitude is half of the range.
a=(maximum-minimum)/2, in this case
a=(2-(-4))/2
a=6/2
a=3
Answer:
Midpoint formula.
The midpoint formula is (x_1+x_2)/2 , (y_1+y_2)/2
Step-by-step explanation:
This is one method. A list wasn't provided.
Answer:
30-2x
Step-by-step explanation:
yuson has to finish am total of 30 hours in community service
she does 2 hours each day
in x days, hour of service done=2x
after x days hours of service left=30-2x
therefore the linear equation representing the hours yuson has left after x days is:
30-2x
Step-by-step explanation:



Get x on one side then you can use substitution
So, change x+3y=3 to x= -3y+3
Then plug in x to other equation to find y
2(-3y +3)-3y=-12
-6y + 6 -3y = -12
-9y = -18
Divide both sides by negative nine to find y
y = 2
Then plug in to original equation to find x
x + 3(2) = 3
x + 6 = 3
x = -3
So, y = 2 and x = -3