Step-by-step explanation:
The elements of matrices are represented in the form
Here r is the row number and c is the column number.
Given matrix is:
![A = \left[\begin{array}{ccc}3&6&9\\2&4&8\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%266%269%5C%5C2%264%268%5Cend%7Barray%7D%5Cright%5D)
The elements of matrix will be represented by a_{r,c}
We have to find 
Which means that the first row and third column.
The first row is: 3 6 9 and the element in third column is: 9
So,
Keywords: Matrices, Elements
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You add the numbers of all 4 sides.
Well the thing is you didn't tell us which number but if it is 12 then i strongly believe that the answer is 3/9
Normally, you would do whatever is inside of the parenthesees first then do the rest but we cant get any further so we remove the parenthasees by distrubtion
7a+6b-4(3a-3b)
-4(3a-3b)
a(b+c)=(ab)+(ac)
-4(3a-3b)=-12a-(-12b)
7a+6b-12a+12b
7a-12a+6b+12b
-5a+18b
that's the asnwer
Answer:
x-3=x+12
Step-by-step explanation:
because some number is x minus 3 would be x-3 is equal to so put an equal sign the product of the number x and 12
