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Free_Kalibri [48]
3 years ago
8

How much thermal energy is in 100 grams of water at 50 degrees Celsius

Chemistry
2 answers:
Ymorist [56]3 years ago
6 0
when the thermal energy is the energy contained within a system that is responsible for its temperature.  

and when the thermal energy  is can be determined by this formula:

q = M * C *ΔT

when q  is the thermal energy

and M is the mass of water = 100 g 

and C is the specific heat capacity of water = 4.18 joules/gram.°C

and T is the difference in Temperature = 50 °C

So by substitution:

∴ q = 100 g * 4.18 J/g.°C * 50

   = 20900 J  = 20.9 KJ
Katena32 [7]3 years ago
6 0

Explanation:

Thermal energy is defined as the internal energy of a substance or object which is due to kinetic energy of its atoms or molecules.

Relation between heat energy, mass and temperature is as follows.

                          q = m \times C \times \Delta T

where,           m = mass

                      C = specific heat

               \Delta T = change in temperature

It is given that mass is 100 g and temperature change is 50^{o}C. Specific heat of water is 4.18 J/g ^{o}C.

Therefore, calculate the energy as follows.

                      q = m \times C \times \Delta T

                         = 100 g \times 4.18 J/g ^{o}C \times 50^{o}C

                         = 20900 J

Thus, we can conclude that thermal energy of water for given values is 20900 J.

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What mass of sodium chloride contains 4.59 x 10 24 formula units?
shtirl [24]
The term formula units means molecules.

Then, what you are looking for is the mass in 4.59*10^24  molecules.

The procedure involves to convert the 4.59 * 10^24 molecules into moles and use the molar mass of the sodium chloride.

1) Number of moles = 4.59 * 10^24 molecules / (6.02 * 10^23 molecules/mol) = 7.62 mol

2) Molar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol

3) mass of NaCl = molar mass *  number of moles = 58.44 g/mol * 7.62 mol = 445.31 g of NaCl

Answer: 445.31 g of NaCl.

 
7 0
2 years ago
What is the name for this molecule? a skeletal model of an 8-carbon zig zag chain. there is a double bond between the first and
yKpoI14uk [10]

The name of the compound by using the <u>IUPAC nomenclature of organic compounds</u> is 1 -octene. The correct option is the last option - 1-octene.

<h3>Nomenclature of Organic compounds</h3>

From the question, we are to determine the name of the given molecule.

To name the compound, we will follow the IUPAC rules.

Some of IUPAC rules are

  • Find the longest continuous carbon chain. Determine the root name for this parent chain.
  • For Alkenes (organic compounds with double bond), number the chain of carbons that includes the C=C so that the C=C has the lower position number. Change “ane” to “ene” and assign a position number to the first carbon of the C=C.

The given compound has 8 carbons and a double bond. The root name of the compound is octane.

By <u>IUPAC rules</u>, the compound is an <u>Octene</u>.

Since the double bond is between carbon-1 and carbon-2. The compound becomes 1-octene.

Hence, the name of the compound by using the <u>IUPAC nomenclature of organic compounds</u> is 1 -octene. The correct option is the last option - 1-octene.

Learn more on Nomenclature of Organic compounds here: brainly.com/question/26754333

The diagram for the compound is attached below.

8 0
2 years ago
An aqueous HCL solution has a proton concentration equal to 6.00 mol/L. The HCL concentration in this solution is ————M.
Harman [31]

Answer:

HCl conc.= 6.0mol/L

Explanation:

From the dissociation of HCl= 1 mole H+ and 1mol Cl-, which is equivalent stoichiometrically in concentration to that of 1 mol HCl,

4 0
3 years ago
Science question down below
aliya0001 [1]
Option 1/A (It is the first one)
6 0
3 years ago
Oh, no! You just spilled 85.00 mL of 1.500 M sulfuric acid on your lab bench and need to clean it up immediately! Right next to
vredina [299]

Explanation:

We will balance equation which describes the reaction between sulfuric acid and sodium bicarbonate: as follows.

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Next we will calculate how many moles of H_2SO_4 are present in 85.00 mL of 1.500 M sulfuric acid.

As,       Molarity = \frac{\text{moles of solute}}{\text{liters of solution&#10;}}

            1.500 M = \frac{n}{0.08500 L&#10;}

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Now set up and solve a stoichiometric conversion from moles of H_2SO_4  to grams of NaHCO_3. As, the molar mass of NaHCO_3 is 84.01 g/mol.

 0.1275 mol H_2SO_4 \times (\frac{2 mol NaHCO_3}{1 mol H_2SO_4}) \times (\frac{84.01 g NaHCO_3}{1 mol NaHCO_3})

                 = 21.42 g NaHCO_3

So unfortunately, 15.00 grams of sodium bicarbonate will "not" be sufficient to completely neutralize the acid. You would need an additional 6.42 grams to complete the task.

4 0
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