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Free_Kalibri [48]
3 years ago
8

How much thermal energy is in 100 grams of water at 50 degrees Celsius

Chemistry
2 answers:
Ymorist [56]3 years ago
6 0
when the thermal energy is the energy contained within a system that is responsible for its temperature.  

and when the thermal energy  is can be determined by this formula:

q = M * C *ΔT

when q  is the thermal energy

and M is the mass of water = 100 g 

and C is the specific heat capacity of water = 4.18 joules/gram.°C

and T is the difference in Temperature = 50 °C

So by substitution:

∴ q = 100 g * 4.18 J/g.°C * 50

   = 20900 J  = 20.9 KJ
Katena32 [7]3 years ago
6 0

Explanation:

Thermal energy is defined as the internal energy of a substance or object which is due to kinetic energy of its atoms or molecules.

Relation between heat energy, mass and temperature is as follows.

                          q = m \times C \times \Delta T

where,           m = mass

                      C = specific heat

               \Delta T = change in temperature

It is given that mass is 100 g and temperature change is 50^{o}C. Specific heat of water is 4.18 J/g ^{o}C.

Therefore, calculate the energy as follows.

                      q = m \times C \times \Delta T

                         = 100 g \times 4.18 J/g ^{o}C \times 50^{o}C

                         = 20900 J

Thus, we can conclude that thermal energy of water for given values is 20900 J.

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Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 13. g of butane is m
12345 [234]

<u>Answer:</u> The maximum amount of water that could be produced by the chemical reaction is 20.16 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For butane:</u>

Given mass of butane = 13 g

Molar mass of butane = 58.12 g/mol

Putting values in equation 1, we get:

\text{Moles of butane}=\frac{13g}{58.12g/mol}=0.224mol

  • <u>For oxygen gas:</u>

Given mass of oxygen gas = 70.9 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

\text{Moles of oxygen gas}=\frac{70.9g}{32g/mol}=2.216mol

The chemical equation for the reaction of butane and oxygen gas follows:

2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O

By Stoichiometry of the reaction:

2 moles of butane reacts with 13 moles of oxygen gas

So, 0.224 moles of butane will react with = \frac{13}{2}\times 0.224=1.456mol of oxygen gas

As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, butane is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of butane produces 10 moles of water

So, 0.224 moles of butane will produce = \frac{10}{2}\times 0.224=1.12moles of water

Now, calculating the mass of water from equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = 1.12 moles

Putting values in equation 1, we get:

1.12mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(1.12mol\times 18g/mol)=20.16g

Hence, the maximum amount of water that could be produced by the chemical reaction is 20.16 grams

8 0
3 years ago
Idenify each statement below as either oxidation or reduction.
Alenkasestr [34]

Answer:

1 = oxidation

2 = reduction

Explanation:

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

2I- ----> I₂+ 2e⁻

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

F + e⁻ ----> F⁻

Consider the following reactions.

4KI + 2CuCl₂  →   2CuI  + I₂  + 4KCl

the oxidation state of copper is changed from +2 to +1 so copper get reduced.

CO + H₂O   →  CO₂ + H₂

the oxidation state of carbon is +2 on reactant  side and on product side it becomes  +4 so carbon get oxidized.

Na₂CO₃ + H₃PO₄  →  Na₂HPO₄ + CO₂ + H₂O

The oxidation state of carbon on reactant side is +4. while on product side is  also +4 so it neither oxidized nor reduced.

H₂S + 2NaOH → Na₂S + 2H₂O

The oxidation sate of sulfur is -2 on reactant side and in product side it is also -2 so it neither oxidized nor reduced.

4 0
3 years ago
Parallelogram PQRS is shown below. Parallelogram P Q R S. Angle P is 116 degrees. Angle R is opposite to angle P. What are the m
aliya0001 [1]

Answer:

64 degrees

Explanation:

5 0
3 years ago
2H2(g)+2NO(g)→2H2O(g)+N2(g) Part A If the concentration of NO changed from 0.100 M to 0.025 M in the first 15 minutes of the rea
andrew11 [14]

Answer:

0.0025 M/min

Explanation:

The rate of a reaction can be calculated for an element, based on its stoichiometric coefficient. For a reaction:

aA + bB = cC + dD , the rate will be

r = -(1/a)x(Δ[A]/Δt) = -(1/b)x(Δ[B]/Δt) = (1/c)x(Δ[C]/Δt) = (1/d)x(Δ[D]/Δt)

Where Δ[X] is the variation of the concentration of the X compound, Δt is the time variation, and the signal of minus in the reagents compounds is because they are disappearing, so Δ[X] will be negative, and r must be positive. So, for the reaction given:

r = -(1/2)x(Δ[NO]/Δt)

r = -(1/2)x( (0.025 - 0.1)/15)

r = 0.0025 M/min

6 0
3 years ago
Which statement is correct?
Harman [31]

Among solids, liquids, and gases, solids generally have the highest entropy because solid particles are the least mobile, and entropy is inversely related to mobility of particles.
7 0
3 years ago
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