Answer:
E cell = +1.95 V
Explanation:
At Anode : Oxidation reaction takes place
At Cathode : Reduction reaction takes place
The reaction with lower value of reduction potential will undergo Oxidation
E = -1.18 V
This equation undergo oxidation reaction and become:
Anode(Oxidation-Half) :
E = +1.18 V
Cathode(Reduction-Half) :
E =+0.77 V
To balance the reaction multiply reduction-Half with 2.We get :

Note that E is intensive property , do not multiply E of oxidation-half with 2
Ecell = 0.77 -(-1.18)
E = +1.95 V
All the layers are important to some degree but in my opinion, the troposphere, as that is the one we live in.
Glucose is converted into pyruvate in a process called Glycolysis which aim in production of energy for most of tissues inside our body... then pyruvate is converted into acetyl coA with the help of pyruvate dehydrogenase enzyme then this acetyl coA enters citric acid cycle for production of more energy
One Acetyl molecule will be produced form one pyruvic acid. and two pyruvic acid molecule will be formed from one glucose molecule during glycolysis. so from
2 acetyl molecules → one glucose molecules.
For 24 acetyl molecules → ??
24*1/2 = 12.
The answer is 12 Glucose molecules.
Answer:
Geiger counter-countering
Explanation:
<span>We have ground strate configurations of electrons,if electrons are filled in order of increasing energy. When there are electrons are in higher orbitals, we have an atom in an excited state.
B, and C are excited states.
In B, 2 electrons can fit in the 4s orbital, and that should fill fully before the 4p orbitals.
In C, the same is true for 5s and 5p
In D, this is not an excited state because 4s fills before 3d</span>